In a set of five consecutive integers, the smallest integer is more than 2/3 the largest. What is the smallest possible value of the sum of the five integers?

Question

goldenticket · Answer

Is that all the terms they give you?

filllip66 · Answer

yep

goldenticket · Answer

oh ok well lets work with what we got

filllip66 · Answer

So I think it is $$x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)$$

goldenticket · Answer

that's a possible answer let me work it out and look up some stuff ok

filllip66 · Answer

then it is $$x>(2/3)5x$$

goldenticket · Answer

Hey what is happing to open study it is shuting down is 58 days?!!?!!?!?!?

filllip66 · Answer

so

sshayer · Answer

let the numbers be x-2,x-1,x,x+1,x+2
let x-2 be smallest and x+2 be greatest
$$x-2>\frac{ 2 }{ 3 }\left( x+2 \right)$$
3x-6>2x+4
3x-2x>4+6
x>10
x-2>10-2
x-2>8
so smallest value is 9

sshayer · Answer

now you find other four values
they are 10,11,12,13
then find 9+10+11+12+13