Question

How could you solve sin^2x=2sinx??

Answer 1

PLS HELP

Answer 2

Will give medals... Really need help though

Answer 3

ALL POSIBLE WAYS

Answer 4

What do you mean by that though?

Answer 5

I MEAN ANY WAY YOU DO IT IT WILL BE CORRECT

Answer 6

NEED MORE EXPLANATION?

Answer 7

Yes, please. I just couldn't figure out how to start it

Answer 8

SO IF WE PUT ANY NUMBER LIKE 1,2,3,4.5 ETC THE PROBLEM WILL WORK

Answer 9

IN THE X SPOT

Answer 10

I can see that you solved it, but what were the steps to figure out that the answer is all reals?

Answer 11

WELL GIVE ME A MIN TO WRITE

Answer 12

SO WHEN YOU HAVE sin^2x=2sinx?? YOU MUST FIGURE WHAT THE X MEANS SO

Answer 13

GOT IT? @greatbritain00

Answer 14

they aren't the same thing

you can get everything on one side and factor

Answer 15

\[\sin^2(x)=2\sin(x) \\ \sin^2(x)-2\sin(x)=0\]
factor the left hand side

Answer 16

notice both terms have a common factor of sin(x)

Answer 17

I KNOW THAT

Answer 18

Oh! I see.

Answer 19

So sinx=0
and sinx=2
Then I just solve for x? Right?

Answer 20

\[\sin^2(x)=2\sin(x) \\ \sin^2(x)-2 \sin(x)=0 \\ \sin(x) [\sin(x)-2]=0 \\ \sin(x)=0 \text{ or } \sin(x)=2\]
yep good

Answer 21

Thank you so much!

Answer 22

remember that sin(x) only can output values between -1 and 1 and 2 is outside the output range
so you only need to focus on sin(x)=0

Answer 23

Sounds good! So x=k (pi)

Answer 24

and KEZ

Answer 25

awesome

Answer 26

lol somehow i knew you meant k is an element of the integers when you wrote KEZ

Answer 27

Great minds think alike