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Some nitrogen at 80.0 psi gauge pressure occupies 13.0 ft^3. Find its volume, in ft^3, at 50.0 psi gauge pressure.
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(80+14.70)/(50+14.70)*13 ft^3 at sea level Zero psi Gauge pressure at sea level is actually 14.70 psi in outer space is simpler 80/50*13 ft^3
@bugman954 Find the water pressure (in kPa) at the 25.0-m level of a water tower containing water 50.0 m deep.
How would I do that one?
1 meter of water is 9.807 kPa you have 25 meters above so 25*9.807
thanks sir
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