According to Descartes' rule of signs, how many possible negative real roots could the following polynomial function have?

Question

nesha97 · Answer

$$3x^4-5x^3+5x^2+5x-2$$

nesha97 · Answer

please help me someone!!!!!

tkhunny · Answer

What is the Rules of Signs?  Substitute -x for x (essentially, just change the sign on all the coefficients with negative exponents) and count the sign changes.

Please show your work.

nesha97 · Answer

ok so when i did that i got
$$3x^4+5x^3+5x^2-5x-2$$
so is it 2 negative roots since it got 2 negatives or is it 1 since it changed to a different type sign only once????

nesha97 · Answer

did i do that right or do i leave the degrees off?

tkhunny · Answer

Doesn't matter.  Only the coefficients are important.

3x4−5x3+5x2+5x−2
+-++- (that's 3 changes)

3x4+5x3+5x2-5x−2
+++-- (that's 1 change)

That's all there is to it.

nesha97 · Answer

ok thank you

satellite73 · Answer

$$\huge 3x^4\color{red}+5x^3\color{red}+5x^2\color{green}-5x\color{green}-2$$