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Mathematics 8 Online
OpenStudy (thekingofcr):

h(t)=-16t^2+175t+500 Please help solve for t

OpenStudy (sooobored):

solve for t, when?

OpenStudy (thekingofcr):

solve for t (time)

OpenStudy (thekingofcr):

@sooobored please help

OpenStudy (sooobored):

you mean write it as a function of t(h)?

OpenStudy (thekingofcr):

well im trying to find t( the time it will take for a firework to launch and then land with ou exploding.

OpenStudy (sooobored):

well thats a completely different question

OpenStudy (sooobored):

you're trying to solve for when h(t)=0 or 0.0000000000000000000000000000000001 though 0 is close enough

OpenStudy (thekingofcr):

oh well can u help 0

OpenStudy (sooobored):

0= -16 t^2 +175t+500 and then you can use the quadratic formula to solve for the roots

OpenStudy (sooobored):

\[t= \frac{-b \pm \sqrt{ b^2 -4ac}}{2a}\] where a=-16 b=175 c=500

OpenStudy (sooobored):

and the negative t answer does not count as an answer

OpenStudy (thekingofcr):

oh so what does the quadratic formula look like

OpenStudy (sooobored):

the -b plus minus is the quadratic formula

OpenStudy (thekingofcr):

do u know the answer for this problem, and can u explain how u got it?

OpenStudy (sooobored):

by plugging in the values into the quadratic equation

OpenStudy (thekingofcr):

can u type out the equation i should plug into

OpenStudy (sooobored):

sorry, quadratic formula

OpenStudy (sooobored):

i already did that above...

OpenStudy (thekingofcr):

formula*

OpenStudy (thekingofcr):

you said the b- ?

OpenStudy (sooobored):

look the quadratic equation given is h(t)=-16 t^2 +175 t +500 the generic quadratic equation is y=ax^2 + bx +c now, the quadratic formula is a formula that gives you the "roots" or x when y=0 and it has the form \[x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\] now in the case of your problem we want to find t (related to x) when h(t) (related to y) is equal to 0 which means we can use the quadratic formula comparing the quadratic equations we get a= -16 b= 175 c= 500 substitute those values into the quadratic formula and you will get 2 different answers

OpenStudy (sooobored):

http://www.purplemath.com/modules/quadform.htm

OpenStudy (sooobored):

look at that if you want examples of how to apply the quadratic formula

OpenStudy (thekingofcr):

i dont get it as well as you do can u please tell the two answers and just show what u did to get that through changing equations

OpenStudy (thekingofcr):

you didn't finish the problem idiot, u have no idea what your talking about your a fake, you have to factor it not do your formula crap!

OpenStudy (welshfella):

This equation won.t factor so you need to use the formula that sooobored gave you.

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