h(t)=-16t^2+175t+500 Please help solve for t
solve for t, when?
solve for t (time)
@sooobored please help
you mean write it as a function of t(h)?
well im trying to find t( the time it will take for a firework to launch and then land with ou exploding.
well thats a completely different question
you're trying to solve for when h(t)=0 or 0.0000000000000000000000000000000001 though 0 is close enough
oh well can u help 0
0= -16 t^2 +175t+500 and then you can use the quadratic formula to solve for the roots
\[t= \frac{-b \pm \sqrt{ b^2 -4ac}}{2a}\] where a=-16 b=175 c=500
and the negative t answer does not count as an answer
oh so what does the quadratic formula look like
the -b plus minus is the quadratic formula
do u know the answer for this problem, and can u explain how u got it?
by plugging in the values into the quadratic equation
can u type out the equation i should plug into
sorry, quadratic formula
i already did that above...
formula*
you said the b- ?
look the quadratic equation given is h(t)=-16 t^2 +175 t +500 the generic quadratic equation is y=ax^2 + bx +c now, the quadratic formula is a formula that gives you the "roots" or x when y=0 and it has the form \[x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\] now in the case of your problem we want to find t (related to x) when h(t) (related to y) is equal to 0 which means we can use the quadratic formula comparing the quadratic equations we get a= -16 b= 175 c= 500 substitute those values into the quadratic formula and you will get 2 different answers
look at that if you want examples of how to apply the quadratic formula
i dont get it as well as you do can u please tell the two answers and just show what u did to get that through changing equations
you didn't finish the problem idiot, u have no idea what your talking about your a fake, you have to factor it not do your formula crap!
This equation won.t factor so you need to use the formula that sooobored gave you.
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