A snow cone is a tasty treat with flavored ice and a spherical bubble gum ball at the bottom, as shown below: The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice?
u will get the answer by substracting the volume of ball from volume of cone
do u have any answer choices
4.43 in3 0.07 in3 13.50 in3 4.50 in3
Do you know the formulas for the volumes of a cone and of a sphere? \(\Large V_{cone} = \dfrac{1}{3} \pi r^2h\) \(\Large V_{sphere} = \dfrac{4}{3} \pi r^3\)
What you have to do is Volume of the cone - volume of the bubble gum. This is: 13πr2h−43πr3
Continuing to solve: \(\[\frac{ 1 }{ 3 }( \pi )(1.25)^2(2.75) - \frac{ 4 }{ 3 } \pi (.25)^3\]
Got it. Thanks
Join our real-time social learning platform and learn together with your friends!