@3
ok what is your choice?
C based off my work.. what you think
Let's agree that that is a quadratic equation comes from a cubic equation, ok?
yes
@3mar
@3mar
Sorry, I was not online! Do you still need help?
@3mar
I am here, thinking about that confusing problem!
@3mar
hello?? @3mar
Yes I saw it! delete it please!
ok! are you working on the problem?
Yes. for sure statement I is not correct. are you agree?
yes!
so that leaves us between choice B and C
what about D?
what is D?
I and III only so its not right.
Yes, D is not right!
Yes B or C, but let me pick the correct one! Time for pray - 45 min - Salam!
ok- please come bacK!!!
@jim_thompson5910 can you finish up please?
I am back!
@3mar ah thank yoU!
No problem at all! I think C, but I want to be sure 100%
In mathematics, a critical point is any value in its domain where its derivative is 0. agree with me?
and yes i agree
An inflection point is a point on a curve at which the sign of the curvature (i.e., the concavity) changes.
so it is C or no??? @3mar
Involve yourself making the decision of this with me!
@3mar
ok I will confirm
No problem.
of course I read about it now
ok
hello?? please!
@3mar !
This is the first derivative. https://www.desmos.com/calculator/i5tpbxgllj and that is the function itself! https://www.desmos.com/calculator/15ywomf9gm I got it now All praise is due to Allah! This function has only an inflection point at x=2 because the concavity of the original function f(x) changes at this point, not a critical point (at x=2 the slope does not equal to zero nor undefined)!
How it is still C,,,did not understand my point??????????
which letter is it?? yes i did
Look at the graph I sent! https://www.desmos.com/calculator/rcwi7kxocm the red curve represents the function f(x), and at x=2 the concavity changes, so at x=2 there is a point of inflection, not a critical point!
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