Question

could someone please check a problem for me please?

Answer 1

@jagr2713

Answer 2

@518nad

Answer 3

Please post whichever thing you want to be reviewed.

Answer 4

this is the first part, which i assume i just look at it,

Answer 5

and this is the second part which i got this

Answer 6

would i do anything for the first par?

Answer 7

@mathmale

Answer 8

@wolf1728

Answer 9

@Vuriffy

Answer 10

What is the given information to transform that image?


The second part seems right since you expressed them in a graphing program.

Answer 11

what do you mean

Answer 12

It says transform the graph according to the given information, for the first picture you posted, what is the given information to transform it?

Answer 13

i would assume it has something to do with this graph

Answer 14

Yes, but I may a little confused on what it is truly asking.
I am not sure if it wants to compare the two different plots displayed in the graph, or if it wishes to transform it in some way.

Maybe @wolf1728 can clear this for me, since I am not a graph person.

Answer 15

You've posted 3 graphs
It seems to me that the a,b,c,d question is answered in the graphoc that shows the straight lines

Answer 16

yes

Answer 17

that is the abcd part we just dont know what the first part means

Answer 18

I have no idea what that 3rd graph (the one shaped like a "U") has to do with anything.

Answer 19

which one?

Answer 20

It would really help if you NAMED those graphs ... but anyway,
the problem with the a,b,c,d parts
is ANSWERED by the graph with the straight lines.
The 3rd graph (shaped like a "U") doesn't seem to figure into this at all.

Answer 21

ok so i will just go with my graphs

Answer 22

Good job.

Answer 23

I have a couple more problems could you guys help me out?

Answer 24

Okay here is the question and answer pasted together.

Answer 25

ok thank you could you help with a couple more?

Answer 26

all right let's try one more

Answer 27

in a new post?

Answer 28

No - you can post it right here

Answer 29

ok is there anyway you could do three more? amd then i promise you im done

Answer 30

Let's try one at a time

Answer 31

ok first one

Answer 32

i think they would be -1,4,2

Answer 33

You are correct!! That's very good that you can solve a cubic equation!

Answer 34

thank you!! 2 more?

Answer 35

Okay go ahead

Answer 36

thank you!!!

Answer 37

Find a third-degree polynomial function with integer coefficients that has 2, 7i, and -7i as zeros.
i have no ide what to do

Answer 38

I'd say you would have to multiply this:
(x-2) * (x-7i) * (x+7i)

Answer 39

x^(3)-2x^(2)+49x-98

Answer 40

I guess those "i" cancel out huh?

Answer 41

yeah i guess

Answer 42

I used my cubic equation calculator here:
http://www.1728.org/cubic.htm
and it seems that you multiplied those correctly!

Answer 43

ok thank you one more?

Answer 44

Okay, one more

Answer 45

Again not a clue

Answer 46

I used my cubic equation calculator again and the answers I got were
2
1 +4i
1 -4i

As far as solving that equation I have a method here:
http://www.1728.org/cubic2.htm
Then again, they do give you 1 answer
1 + 4i
so that must help you out somehow.

Answer 47

i just need the zeros, so they would be
2
1 +4i
1 -4i

Answer 48

Yes, that is correct.

Answer 49

ok thank you so much

Answer 50

u r welcome and please visit my website it could help you with other math prolems
http://www.1728.org/

Answer 51

ok could you help me tomorrow night?

Answer 52

@wolf1728