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Mathematics 14 Online
OpenStudy (theoneandonly):

Help? http://prntscr.com/dgcroo http://prntscr.com/dgcslu

MARC (marc_d):

First question,choose any point which is related to the curve...

MARC (marc_d):

let say i choose point(1,0)

MARC (marc_d):

MARC (marc_d):

\[point(1,0)=(x,y)\]

MARC (marc_d):

to determine which eqn is correct,sub. x=1 into each equations... if u got the value of y which is = 0,therefore,that is the eqn related to that curve...

MARC (marc_d):

i will show the how to do for option A n u will need to do the rest...

MARC (marc_d):

option A f(x)=3log(x)

MARC (marc_d):

sub. x=1 into the eqn

MARC (marc_d):

\[f(x)=3\log_{10}\color{red}{1}\]

MARC (marc_d):

bring down the power\[f(x)=\log_{10}1^\color{red}{3}\]

MARC (marc_d):

\[f(x)=0\]noted that f(x)=y

MARC (marc_d):

hmmm,it seems that point(1,0) can used in all eqns...

MARC (marc_d):

okay,let's try point(1,3)

MARC (marc_d):

option A f(x)=3log(x)

OpenStudy (theoneandonly):

I graphed D and believe thats the answer http://prntscr.com/dgd0mz

MARC (marc_d):

answer is not D... @Theoneandonly

OpenStudy (theoneandonly):

ohh the curve has to be higher

MARC (marc_d):

yep,that's right! :)

OpenStudy (theoneandonly):

alright I believe its B http://prntscr.com/dgd1um

MARC (marc_d):

yep,that's correct!

OpenStudy (theoneandonly):

ok c:

MARC (marc_d):

if u want to double check it,use any point which is on the curve...

OpenStudy (jerry45):

close this pleas ;-;

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