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URGENT plz help exponents problem!!
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If ax^k = x^k+1, and a, k, x are all positive integers greater than 1, what is the value of (a-x/k)?
is the k+1 in exponent or just k ?
\[a x^k = x^k+1 \]
@Nfreeman just k is the exponent of x
what is the value of \[\frac{ a-x }{ k }\]
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\[x^{k}(a-1)=1\]
\[x ^{k}=\frac{ 1 }{ a-1 }\]
\[k \ln x = -\ln (a-1)\]
not really any progress so far, let me rethink about this
wait a second, a,k,x are elements of Z+ and greater than 1
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hi @caozeyuan thanks for your help! the answer is x=2 but I don't know how to get there
do you mean (a-x)/k is 2?
yes, sorry the value of (a-x)/k is 2
@ mathmale, can you take a look, my brain is not strong enough to deal with this question
@mathmale
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