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@3mar brother help please
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Sorry for being late!
\[(x-1)^2=x^2-2x+1\]
@zarkam21 Firstly, you have to expand the right-hand side parenthesis and don't forget to distribute 4 to the output!
ax^2+bx+c=0 is the standard form of quadratic eq. where a,b,c are constants.
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Um :(
Start by expanding this: (x-1)^2.
i have given the formula for (x-1)^2
So (x-1)(x+1)?
@zarkam21 Tell me where are you are stuck in order to I can help you!
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YES, that is the key! Do this multiplication!
is it 4x^2?
I mean \((x-1)^2=(x-1)(x-1)\)
and then
then multiply :|dw:1481165592203:dw|
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