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Mathematics 17 Online
zarkam21 (zarkam21):

@3mar brother help please

zarkam21 (zarkam21):

OpenStudy (3mar):

Sorry for being late!

OpenStudy (sshayer):

\[(x-1)^2=x^2-2x+1\]

OpenStudy (3mar):

@zarkam21 Firstly, you have to expand the right-hand side parenthesis and don't forget to distribute 4 to the output!

OpenStudy (sshayer):

ax^2+bx+c=0 is the standard form of quadratic eq. where a,b,c are constants.

zarkam21 (zarkam21):

Um :(

OpenStudy (mathmale):

Start by expanding this: (x-1)^2.

OpenStudy (sshayer):

i have given the formula for (x-1)^2

zarkam21 (zarkam21):

So (x-1)(x+1)?

OpenStudy (3mar):

@zarkam21 Tell me where are you are stuck in order to I can help you!

OpenStudy (3mar):

YES, that is the key! Do this multiplication!

zarkam21 (zarkam21):

is it 4x^2?

OpenStudy (3mar):

I mean \((x-1)^2=(x-1)(x-1)\)

zarkam21 (zarkam21):

and then

OpenStudy (3mar):

then multiply :|dw:1481165592203:dw|

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