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Mathematics 15 Online
OpenStudy (kaedalozzano10):

What is the area of the shaded part of the figure? A. 144 mm² B. 288 mm² C. 432 mm² D. 720 mm² here is the link https://static.k12.com/calms_media/media/1388500_1389000/1388545/1/1eabe39f7c4f89c2c50889b2393d95e6835377b4/62368_FGA_U3_L7_V1_P.jpg

OpenStudy (kaedalozzano10):

can some one help me

OpenStudy (mathstudent55):

Find the area of the triangle and subtract the area of the square.

OpenStudy (mathstudent55):

Do you know how to find the area of a triangle?

OpenStudy (kaedalozzano10):

yes

OpenStudy (kaedalozzano10):

\[a =base \times hieght \]

OpenStudy (mathstudent55):

divided by 2

OpenStudy (mathstudent55):

\(\large A_{triangle} = \dfrac{base \times height}{2} \)

OpenStudy (mathstudent55):

What are the base and height of the triangle?

OpenStudy (kaedalozzano10):

the bas is 24 and the height is 12

OpenStudy (mathstudent55):

Good. Can you now find the area of the triangle?

OpenStudy (kaedalozzano10):

ok i got 144 as my answer

OpenStudy (kaedalozzano10):

so is that right

OpenStudy (mathstudent55):

That is your final answer for the shaded area? If so it is correct.

OpenStudy (mathstudent55):

Area of triangle = 24 mm * 24 mm / 2 = 288 mm^2 Area of square = 12 mm * 12 mm = 144 mm^2 Shaded area = area of triangle - area of square = 288 mm^2 - 144 mm^2 = 144 mm^2

OpenStudy (kaedalozzano10):

ok thanks

OpenStudy (mathstudent55):

You're welcome.

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