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Given the position function s(t), s(t) = t2 + 3t + 1, where s is measured in meters and t is in seconds, find the velocity and acceleration of the particle at t = 4 seconds. 11 m/sec; 2 m/sec2 2 m/sec; 0 m/sec2 11 m/sec; 0 m/sec2 12 m/sec; 2 m/sec2
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Wet C
How did you find out C is the answer?
Can I use Calculus or should I do it without it
First derivative of position function gives velocity, second derivative gives acceleration
First derivative I got 2t+3
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First derivative : 2t + 3 if t = 4, 2t + 3 = 11 Second derivative : 2
second i just got 2
So A?
Answer is A btw that guys is wrong
yup
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