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Mathematics
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OpenStudy (itrymath):
need help asap pLEASE
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OpenStudy (itrymath):
OpenStudy (itrymath):
@sshayer
OpenStudy (sshayer):
can you show me how for you know?
OpenStudy (sshayer):
any idea.
OpenStudy (itrymath):
hold on
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OpenStudy (itrymath):
lemmy have a look
OpenStudy (itrymath):
no idea
OpenStudy (sshayer):
\[\sqrt{56}=\sqrt{4 \times 14}=2 \sqrt{14}\]
\[\sqrt{126}=\sqrt{9 \times 14}=?\]
OpenStudy (itrymath):
\[3\sqrt{14}\]
OpenStudy (sshayer):
correct.
can you solve first?
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OpenStudy (itrymath):
answer is A
OpenStudy (sshayer):
\[a \sqrt{x}+b \sqrt{x}-c \sqrt{x}-d \sqrt{x}=\left( a+b-c-d \right)\sqrt{x}\]
OpenStudy (itrymath):
OHHH its B
OpenStudy (sshayer):
correct.
OpenStudy (itrymath):
oaky second one
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OpenStudy (sshayer):
\[a \sqrt{x}*b \sqrt{y}=a*b \sqrt{x*y}\]
both x and y should not be negative.
OpenStudy (sshayer):
10*5=50=25*2
OpenStudy (itrymath):
?
OpenStudy (sshayer):
\[\sqrt{10*5}=\sqrt{50}=\sqrt{25*2}=?\]
OpenStudy (itrymath):
its a decimal
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OpenStudy (sshayer):
solve as in first.
OpenStudy (itrymath):
\[12.5\sqrt{2}\]
OpenStudy (sshayer):
\[\sqrt{25}=?\]
OpenStudy (itrymath):
oh 5
OpenStudy (itrymath):
i divided by 2
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OpenStudy (sshayer):
\[7*3*5\sqrt{2}=?\]
\[7\sqrt{10}*3\sqrt{5}=7*3\sqrt{10*5}=21\sqrt{50}=21\sqrt{25 *2}=21*5\sqrt{2}=?\]
OpenStudy (sshayer):
21*5=?
OpenStudy (itrymath):
105
OpenStudy (sshayer):
now you got your option or not.
OpenStudy (itrymath):
B
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OpenStudy (sshayer):
correct.
OpenStudy (itrymath):
okay thanks so much!!
OpenStudy (itrymath):
i have more questions if you dont mind
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