Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (itrymath):

need help asap pLEASE

OpenStudy (itrymath):

OpenStudy (itrymath):

@sshayer

OpenStudy (sshayer):

can you show me how for you know?

OpenStudy (sshayer):

any idea.

OpenStudy (itrymath):

hold on

OpenStudy (itrymath):

lemmy have a look

OpenStudy (itrymath):

no idea

OpenStudy (sshayer):

\[\sqrt{56}=\sqrt{4 \times 14}=2 \sqrt{14}\] \[\sqrt{126}=\sqrt{9 \times 14}=?\]

OpenStudy (itrymath):

\[3\sqrt{14}\]

OpenStudy (sshayer):

correct. can you solve first?

OpenStudy (itrymath):

answer is A

OpenStudy (sshayer):

\[a \sqrt{x}+b \sqrt{x}-c \sqrt{x}-d \sqrt{x}=\left( a+b-c-d \right)\sqrt{x}\]

OpenStudy (itrymath):

OHHH its B

OpenStudy (sshayer):

correct.

OpenStudy (itrymath):

oaky second one

OpenStudy (sshayer):

\[a \sqrt{x}*b \sqrt{y}=a*b \sqrt{x*y}\] both x and y should not be negative.

OpenStudy (sshayer):

10*5=50=25*2

OpenStudy (itrymath):

?

OpenStudy (sshayer):

\[\sqrt{10*5}=\sqrt{50}=\sqrt{25*2}=?\]

OpenStudy (itrymath):

its a decimal

OpenStudy (sshayer):

solve as in first.

OpenStudy (itrymath):

\[12.5\sqrt{2}\]

OpenStudy (sshayer):

\[\sqrt{25}=?\]

OpenStudy (itrymath):

oh 5

OpenStudy (itrymath):

i divided by 2

OpenStudy (sshayer):

\[7*3*5\sqrt{2}=?\] \[7\sqrt{10}*3\sqrt{5}=7*3\sqrt{10*5}=21\sqrt{50}=21\sqrt{25 *2}=21*5\sqrt{2}=?\]

OpenStudy (sshayer):

21*5=?

OpenStudy (itrymath):

105

OpenStudy (sshayer):

now you got your option or not.

OpenStudy (itrymath):

B

OpenStudy (sshayer):

correct.

OpenStudy (itrymath):

okay thanks so much!!

OpenStudy (itrymath):

i have more questions if you dont mind

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!