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Mathematics 21 Online
OpenStudy (ballislife):

Can someone help please?

OpenStudy (ballislife):

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

you know how to find the slope of a line?

OpenStudy (ballislife):

hey

OpenStudy (ballislife):

yes, but I'm doin something wrong

OpenStudy (misty1212):

probably your the sign, it should be negative since the time is getting shorter

OpenStudy (ballislife):

should it be\[\frac{ 3.81-3.91 }{ 1960-1980}\]

OpenStudy (misty1212):

in 20 years it goes from \(3.91\) to \(3.81\) a decrease if \(0.10\) divided by 20 you get \(-0.005\)

OpenStudy (misty1212):

something wrong with your slope, should be \[\frac{3.81-3.91}{1980-1960}\]

OpenStudy (misty1212):

at any rate it has to be negative

OpenStudy (ballislife):

It says its wrong

OpenStudy (misty1212):

that is because your answer is not supposed to be a slope, it is supposed to be the equation of a line

OpenStudy (misty1212):

since 1960 is the starting point, the y intercept is \(3.91\) so your equation should be \[y=-0.005x+3.91\]

OpenStudy (misty1212):

actually you are supposed to use \(t\) so \(-0.005t+3.91\)

OpenStudy (ballislife):

it says thats wrong

OpenStudy (ballislife):

no wait i was supposed to use t instead of x

OpenStudy (ballislife):

thx though

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