The Sum of three consecutive even integers is 980. Determine the integers.
HI!!
guess and check, not algebra try 320, 322, 324 if that doesn’t work, adjust
Actually, I need help in the thing that we need to use Quadratics to find the numbers.
that doesnt' work @satellite73 \[320+322+324=966\]
Like using Quadratic Formula, Discriminant, Completing the square.
yeah @misty1212 i know, i was just giving a start since that is too low, up them
hmm ok i see but no quadratic formula right?
I actually don't get what your trying to say.
nope if you want to do it the math teacher way, solve \[n+n+2+n+4=980\]
isnt that just \(3n+6=980\)?
Satellite73, then what does N represent?
the first number
okay, I actually don't understand. It's a thinking question.
consecutive even means like \[324,326,328\]
Yes yes. But how do you do it?
so if the first one is \(n\) then the second is \(n+2\) and the third is \(n+4\)
you can solve \[3n+6=980\] right @HaziqueAqeel2971 ?
Please explain me.
What do you mean by 3n+6? Is it possible using some quadratic things?
Using the quadratic formula? Using the completing the square?
quadratic means the degree is 2, like \(x^2+6x=18\)
Lol, sorry. I am really sorry if you don't understand.
this is just a linear equation, solve in two steps
Okay, tell me how too. :D
subtract 6, divide by 3
Ohhh. Then?
then you are donej
\[3n+6=980\] subtract 6 from both sides, then divide both sides by 3, that will give you the first number of the three you are looking for
Why 3n+6?
explanation is above
Okay, I saw it. But why did you put 2 + 4?
I agree with satellite73 here: n+n+2+n+4=980 think what these terms represent: n is the first term. n+2 is the first even number following n. n+4 is the second even number following n. n + n+2 + n+4 is the sum of 3 consecutive even numbers, and this sum is equal to 980. Hope this helps make a little clearer what is happening here.
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