Question

3 geom questions! please help

Answer 1

what is a "lateral area"??

Answer 2

base and height?

Answer 3

idk i was asking

Answer 4

a quick google search tells me it is \[(2L+2W)H\]

Answer 5

so \[(2\times 14+2\times 18)\times 2.54\]

Answer 6

oh whoops
okay so that would be 162.56

Answer 7

want me to check?

Answer 8

yeah, that is what i get

Answer 9

but i just googled it, so don't take my word for it
is that a possible answer?

Answer 10

no :/
hold on let me reread the question to see if i missed something

Answer 11

nope, it's not an answer

Answer 12

ok so i googled again, says is is the surface area except the top and the bottom

Answer 13

oh okay hold on I'm gonna try and see what I can do

Answer 14

oh lord!!

Answer 15

it is 8, not 18 doh

Answer 16

Oh its okay lmao
i made the same mistake

Answer 17

i should learn to read \[(2\times 14+2\times 8)\times 2.54\]

Answer 18

111.76 which is an answer, yay!

Answer 19

now just for the surface area

Answer 20

take that number, add the areas of the top and bottom

Answer 21

ok \[11.76+2\times 14\times 8\]

Answer 22

235.76 which isn't an answer

Answer 23

grrr

Answer 24

mkay hold on sorry if this is frustrating

Answer 25

oh i got it! it's 335

Answer 26

wait, it is about 336 right?

Answer 27

yep! my bad

Answer 28

i'm very confused about 6 and 7 tho

Answer 29

i think the squareroot sign throws me off

Answer 30

@3mar

Answer 31

Well, I am here.
How could I help you?

Answer 32

sorry to bother, but I need to figure out how to do number 6 and I'm confused on 7

Answer 33

3 is done?

Answer 34

mhm figured it out

Answer 35

Great!

Answer 36

Could you give me 10 min, please so I will be with you???

Answer 37

hm?

Answer 38

yeah its fine if you leave for a while i'm not in a rush

Answer 39

I am with you now

Answer 40

Sorry for being late for you

Answer 41

its okay

Answer 42

Any pyramid has number of faces equal to the number of sides of its base!

and this one has six (equal) faces, and the area of one of them is calculated as follows: