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Mathematics 14 Online
MARC (marc_d):

Sketch the graph of @mathmale

MARC (marc_d):

\[y=3+|x+1|\]

MARC (marc_d):

\[y=\color{red}{3}+|x+1| \]

MARC (marc_d):

The value of 3 is only use for y or...

OpenStudy (mathmale):

That 3 is a y-value. If x=-1, then the second term, |x+1|, will be zero. In your shoes I would start by graphing the abs. value function y=|x|. Can y ou do that now?

MARC (marc_d):

yes

OpenStudy (sshayer):

when y=3,x=-1 when x=-2,y=4 x=1,y=5 when x=-3,y=5 |dw:1481252616848:dw|

OpenStudy (mathmale):

Once you have graphed y=|x|, you translate your graph UP by 3 units and to the left by 1 unit. Let's discuss why this is so.

MARC (marc_d):

okay.

OpenStudy (mathmale):

With practice you'll be able to graph this with hardly a 2nd thought. But for now, graph the basic function y=|x|.

MARC (marc_d):

alright..

MARC (marc_d):

|dw:1481252941738:dw|

OpenStudy (mathmale):

|dw:1481253017526:dw|

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