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Sketch the graph of @mathmale
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\[y=3+|x+1|\]
\[y=\color{red}{3}+|x+1| \]
The value of 3 is only use for y or...
That 3 is a y-value. If x=-1, then the second term, |x+1|, will be zero. In your shoes I would start by graphing the abs. value function y=|x|. Can y ou do that now?
yes
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when y=3,x=-1 when x=-2,y=4 x=1,y=5 when x=-3,y=5 |dw:1481252616848:dw|
Once you have graphed y=|x|, you translate your graph UP by 3 units and to the left by 1 unit. Let's discuss why this is so.
okay.
With practice you'll be able to graph this with hardly a 2nd thought. But for now, graph the basic function y=|x|.
alright..
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|dw:1481252941738:dw|
|dw:1481253017526:dw|
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