Question

how can i find the inflection point of the equation,
dy/dx=(a-y)(b+y)

Answer 1

\[\frac{ d^2y }{ dx^2 }=\left( a-y \right)\frac{ dy }{ dx }+\left( b+y \right)\left( \frac{ -dy }{ dx } \right)\]
\[=\left( a-y-b-y \right)\frac{ dy }{ dx }=\left( a-b-2y \right)\left( a-y \right)\left( b+y \right)\]
at point of inflection
\[\frac{ d^2y }{ dx ^2}=0\]
\[y=a,-b,\frac{ a-b }{ 2 }\]

Answer 2

nope