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Mathematics 15 Online
OpenStudy (societyyay):

This limit @.Sam.:

OpenStudy (societyyay):

OpenStudy (societyyay):

hope u can read it

sam (.sam.):

Evaluate what?

OpenStudy (societyyay):

of f(x): x =0 and x=1.5

OpenStudy (societyyay):

its a piecewise function

sam (.sam.):

You've got the x when \(x \rightarrow 0^-\), that's ln(2) \[\lim_{x \rightarrow 1^-}(x-2)=-1 ~~~~~~~ \lim_{x \rightarrow 1.5+}(x-2)=-0.5\]

OpenStudy (societyyay):

okay but limit approaching 1? shouldn't it be 0 postive

OpenStudy (societyyay):

also its \[|x -2|\]

sam (.sam.):

Approaching 1? That's what I thought at first because you wrote 1 there

sam (.sam.):

And you split the absolute function to left hand and right hand limit

OpenStudy (societyyay):

okay cool so when lim 0 positive its the absolute one x-2 ?

OpenStudy (societyyay):

this is clear, hope u can read it now

OpenStudy (societyyay):

so for the x=1.5 should i use the middle function? or the last one?

OpenStudy (sshayer):

is it defined at x=0?

OpenStudy (sshayer):

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