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This limit @.Sam.:
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hope u can read it
Evaluate what?
of f(x): x =0 and x=1.5
its a piecewise function
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You've got the x when \(x \rightarrow 0^-\), that's ln(2) \[\lim_{x \rightarrow 1^-}(x-2)=-1 ~~~~~~~ \lim_{x \rightarrow 1.5+}(x-2)=-0.5\]
okay but limit approaching 1? shouldn't it be 0 postive
also its \[|x -2|\]
Approaching 1? That's what I thought at first because you wrote 1 there
And you split the absolute function to left hand and right hand limit
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okay cool so when lim 0 positive its the absolute one x-2 ?
this is clear, hope u can read it now
so for the x=1.5 should i use the middle function? or the last one?
is it defined at x=0?
|dw:1481412871375:dw|
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