Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (itrymath):

number 3 :)

OpenStudy (itrymath):

@sunnnystrong

OpenStudy (sunnnystrong):

\[f(x)=12500(0.82)^x\] f(x)= Price of product A ($) x= Time (Years) Part A.) Is f(x) increasing or decreasing? By what percentage? So, to answer this problem we have to find the decay factor (as f(x) is clearly decreasing)... How would we do that?

OpenStudy (sunnnystrong):

Exponential Decay: \[A=A _{0}b^t\] 0<b<1 A\[A_{0}=initial\]

OpenStudy (itrymath):

we would plug in the numbers of years we need to from the grpah provided ?

OpenStudy (itrymath):

yes, tho im not sure

OpenStudy (sunnnystrong):

Oh sorry... so We COULD graph the function and look at how the y values change each year and find a percentage but it is easier to just remember that: Rate of decay = (1-b)

OpenStudy (sunnnystrong):

If b= 0.82 (from the equation) What is the rate of decay?

OpenStudy (sunnnystrong):

OpenStudy (sunnnystrong):

Another picture ^^ This can apply to exponential decay if: 0<b<1***

OpenStudy (itrymath):

if only i knew wha that meant ^

OpenStudy (itrymath):

lmao im stuid, its 0.82

OpenStudy (sunnnystrong):

Oh sorry haha well... that is just the general form of exponential decay/increase. Basically: Our function:\[f(x)=12500(0.82)^x\] Where 12500= initial starting amount 0.82= Rate x=time Our rate of decay is 1-Rate

OpenStudy (sunnnystrong):

@ItryMath no... close. It'll be 1-0.82

OpenStudy (itrymath):

so 0.18 is rate of decay?

OpenStudy (sunnnystrong):

Yep :D

OpenStudy (itrymath):

okay

OpenStudy (itrymath):

LIKE HOW ARE YOU NOT A PROFESSOR ?!?!

OpenStudy (itrymath):

sorry caps

OpenStudy (sunnnystrong):

@ItryMath lol nahh XD i still have a lot of school ahead of me haha but for the next one: Can you make a function for exponential decay based on the given table?

OpenStudy (itrymath):

imean 12500(0.18)^x and what do you want to be (your major)

OpenStudy (sunnnystrong):

Welll.... 0.18 is the percent increase but overall the DECAY factor is a single value 1-0.18 & computer engineering :D

OpenStudy (sunnnystrong):

but that is for the first one.. the second one is different. look carefully at the table. The initial point is (1, 5600)

OpenStudy (sunnnystrong):

percent decrease***^

OpenStudy (itrymath):

*Jaw Drops*

OpenStudy (itrymath):

whats the first one???

OpenStudy (sunnnystrong):

Part A.) We both agreed it's 18% decrease. Moving on to part B --> Can you write a function for the given table?

OpenStudy (itrymath):

oh okay

OpenStudy (itrymath):

sorry my brain stops working around 10 and its 11 rn and i reall am trying lmao but im stupid rn

OpenStudy (itrymath):

i dont want you to do all the work even though you seem to be

OpenStudy (sunnnystrong):

No it's okay i'm actually just bored at home lol

OpenStudy (sunnnystrong):

But it's cool I should let you do it XD

OpenStudy (itrymath):

Be my tutor PLEASE i'll pay you big $$$$

OpenStudy (itrymath):

$$

OpenStudy (sunnnystrong):

no it's okay lol :P

OpenStudy (itrymath):

i know the function should be in a(b)^x form so x would be 1 b would be not sure and a is 5600

OpenStudy (itrymath):

crying because life just go harder xD

OpenStudy (sunnnystrong):

Well, you are right I agree with you. The function will look something like: \[A=A _{0}(1-b)^x\] Where \[A _{0}=initial \] b=percent of decay x=time

OpenStudy (itrymath):

x=1 b = ?!??!?///????

OpenStudy (sunnnystrong):

x doesn't always equal 1... x=time b=rate of decay. Basically: f(1)-f(2)=??? That number/f(1)=b

OpenStudy (sunnnystrong):

@ItryMath can you find b? ^^

OpenStudy (itrymath):

oh yes of course (back)

OpenStudy (itrymath):

2464

OpenStudy (itrymath):

sorry took so long ... im in lake tahoe so this obviously isnt my house where everything is set up xD

OpenStudy (itrymath):

I mean 1 day i plane to own houses around the world because i hate hotes like hate hate them but that requires math and graphs etc :(

OpenStudy (sunnnystrong):

hm... no. try and think about it. General process: f(1)-f(2)=??? That number/f(1)=b

OpenStudy (itrymath):

-2464

OpenStudy (itrymath):

i dont know tbh .....

OpenStudy (sunnnystrong):

f(2)=3136 f(1)=5600 5600-3136=2464 2464/5600= 0.44

OpenStudy (sunnnystrong):

0.44=percent of decay So what is the function?

OpenStudy (itrymath):

o we divide after -_-

OpenStudy (sunnnystrong):

yeah sorry lol but i feel like you got this. whats the function?

OpenStudy (itrymath):

no you dont lmao

OpenStudy (itrymath):

5600(0.44)^x

OpenStudy (sunnnystrong):

Almost!!!! and yes i do :D

OpenStudy (sunnnystrong):

What did we talk about ... there is a percent of decay & a DECAY FACTOR... (1-b)....

OpenStudy (itrymath):

(-0.44)

OpenStudy (sunnnystrong):

no. b=0.44.... 1-0.44 does not equal -0.44

OpenStudy (itrymath):

0.56

OpenStudy (sunnnystrong):

Yep. Than you pretty much have all of the info you need to answer B confidently (:

OpenStudy (itrymath):

OOOMMGGG

OpenStudy (itrymath):

WOOOO

OpenStudy (itrymath):

You saved me.... you realize that... you would become an awesome doctor xD

OpenStudy (itrymath):

okay well imma go to sleep thanks so much!

OpenStudy (sunnnystrong):

@ItryMath XD That's very nice! And it is always my pleasure :D Take care!!

OpenStudy (itrymath):

@jim_thompson5910 doesn't product B have the greatest percentage change?

jimthompson5910 (jim_thompson5910):

What's the full problem again @ItryMath ?

OpenStudy (itrymath):

jimthompson5910 (jim_thompson5910):

what percent change did you get for B?

OpenStudy (itrymath):

56%

OpenStudy (itrymath):

and 18% for A

jimthompson5910 (jim_thompson5910):

you should find that 1+r = 0.56 solve for r

OpenStudy (itrymath):

1.56

OpenStudy (itrymath):

So B right...

jimthompson5910 (jim_thompson5910):

1+r = 0.56 does not lead to r = 1.56 try again

jimthompson5910 (jim_thompson5910):

it might be helpful to think of `1+r` as `r+1`

OpenStudy (itrymath):

oh oops sorry!

OpenStudy (itrymath):

-0.44

OpenStudy (itrymath):

wait so it isnt 56 %.... its 44

jimthompson5910 (jim_thompson5910):

yes so A is decaying by 18% while B is decaying by 44%

jimthompson5910 (jim_thompson5910):

in part A, the value of r is 1+r = 0.82 1+r-1 = 0.82-1 r = -0.18 The negative r value indicates decay

OpenStudy (itrymath):

so A is decaaying more, is that what you're trying to say @jim_thompson5910

jimthompson5910 (jim_thompson5910):

A is decaying by 18% each year B is decaying by 44% each year

jimthompson5910 (jim_thompson5910):

B is decaying more each year

OpenStudy (itrymath):

oh so i was right, sorry i got confused lol

OpenStudy (itrymath):

@jim_thompson5910 thanks !!!

OpenStudy (itrymath):

(:

jimthompson5910 (jim_thompson5910):

the negatives probably threw you off

OpenStudy (itrymath):

yes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!