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OpenStudy (itrymath):
@sunnnystrong
OpenStudy (sunnnystrong):
\[f(x)=12500(0.82)^x\]
f(x)= Price of product A ($)
x= Time (Years)
Part A.)
Is f(x) increasing or decreasing? By what percentage?
So, to answer this problem we have to find the decay factor (as f(x) is clearly decreasing)... How would we do that?
we would plug in the numbers of years we need to from the grpah provided ?
OpenStudy (itrymath):
yes, tho im not sure
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OpenStudy (sunnnystrong):
Oh sorry... so
We COULD graph the function and look at how the y values change each year and find a percentage
but it is easier to just remember that:
Rate of decay =
(1-b)
OpenStudy (sunnnystrong):
If b= 0.82 (from the equation)
What is the rate of decay?
OpenStudy (sunnnystrong):
OpenStudy (sunnnystrong):
Another picture ^^ This can apply to exponential decay if:
0<b<1***
OpenStudy (itrymath):
if only i knew wha that meant ^
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OpenStudy (itrymath):
lmao im stuid, its 0.82
OpenStudy (sunnnystrong):
Oh sorry haha well...
that is just the general form of exponential decay/increase.
Basically:
Our function:\[f(x)=12500(0.82)^x\]
Where 12500= initial starting amount
0.82= Rate
x=time
Our rate of decay is 1-Rate
OpenStudy (sunnnystrong):
@ItryMath no...
close.
It'll be 1-0.82
OpenStudy (itrymath):
so 0.18 is rate of decay?
OpenStudy (sunnnystrong):
Yep :D
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OpenStudy (itrymath):
okay
OpenStudy (itrymath):
LIKE HOW ARE YOU NOT A PROFESSOR ?!?!
OpenStudy (itrymath):
sorry caps
OpenStudy (sunnnystrong):
@ItryMath lol nahh XD i still have a lot of school ahead of me haha but for the next one:
Can you make a function for exponential decay based on the given table?
OpenStudy (itrymath):
imean 12500(0.18)^x
and what do you want to be (your major)
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OpenStudy (sunnnystrong):
Welll.... 0.18 is the percent increase but overall the DECAY factor is a single value 1-0.18
& computer engineering :D
OpenStudy (sunnnystrong):
but that is for the first one.. the second one is different. look carefully at the table.
The initial point is (1, 5600)
OpenStudy (sunnnystrong):
percent decrease***^
OpenStudy (itrymath):
*Jaw Drops*
OpenStudy (itrymath):
whats the first one???
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OpenStudy (sunnnystrong):
Part A.) We both agreed it's 18% decrease.
Moving on to part B -->
Can you write a function for the given table?
OpenStudy (itrymath):
oh okay
OpenStudy (itrymath):
sorry my brain stops working around 10 and its 11 rn and i reall am trying lmao but im stupid rn
OpenStudy (itrymath):
i dont want you to do all the work even though you seem to be
OpenStudy (sunnnystrong):
No it's okay i'm actually just bored at home lol
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OpenStudy (sunnnystrong):
But it's cool I should let you do it XD
OpenStudy (itrymath):
Be my tutor PLEASE i'll pay you big $$$$
OpenStudy (itrymath):
$$
OpenStudy (sunnnystrong):
no it's okay lol :P
OpenStudy (itrymath):
i know the function should be in a(b)^x form so x would be 1 b would be not sure and a is 5600
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OpenStudy (itrymath):
crying because life just go harder xD
OpenStudy (sunnnystrong):
Well, you are right I agree with you.
The function will look something like:
\[A=A _{0}(1-b)^x\]
Where \[A _{0}=initial \]
b=percent of decay
x=time
OpenStudy (itrymath):
x=1 b = ?!??!?///????
OpenStudy (sunnnystrong):
x doesn't always equal 1... x=time
b=rate of decay.
Basically:
f(1)-f(2)=???
That number/f(1)=b
OpenStudy (sunnnystrong):
@ItryMath can you find b? ^^
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OpenStudy (itrymath):
oh yes of course (back)
OpenStudy (itrymath):
2464
OpenStudy (itrymath):
sorry took so long ... im in lake tahoe so this obviously isnt my house where everything is set up xD
OpenStudy (itrymath):
I mean 1 day i plane to own houses around the world because i hate hotes like hate hate them but that requires math and graphs etc :(
OpenStudy (sunnnystrong):
hm... no. try and think about it.
General process:
f(1)-f(2)=???
That number/f(1)=b
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