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I need the answer for this question please !se a table of numerical values of f(x, y) for (x, y) near the origin to make a conjecture about the value of the limit of f(x, y) as (x,y) ->(0,0) f(x,y) =x^2*y^3+x^3*Y2-3/ (1-xy)
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linearise it !
how can I linearise it ?!
well, currently, you want x and y to be zero. so your answer is zero.
there is no Zero in the multiple choices
3 or -1 or -3 or 1 or the value can not be determined
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?
perhaps i am reading this the wrong way. and maybe, i think, it's this: \(f(x,y) =x^2y^3+x^3y^2-\dfrac{3}{1-xy} \) so then \(f(0,0) = - \dfrac{3}{1}\) IOW you don't need a table does that make any sense to you?? doesn't to me :(
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