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@3mar brother is this correct?
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HI!!
still at these i see
Yes dear :/
It's correct
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you got it, must know this by now huh?
Well I solve it and I get a square root for a problem. For instance this problem I got\[x=\frac{ 11+\sqrt{53} }{ 2}\]
I didn't know what the second value would be, so would it always just be the same problem but "-"
that is correct, but also \[x=\frac{ 11-\sqrt{53} }{ 2}\]
ususally abbreviated as \[x=\frac{ 11\pm\sqrt{53} }{ 2}\]
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quadratic formula is mostly written with the \(\pm\) meaning two number, one with plus, one with minus \[\huge \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
Oh okay
Thanks cupcake
\[\color\magenta\heartsuit\]
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