Write the point-slope form of the equation passing through (5, -1) with a slope of 6. y-1=6(x+5) y+5=6(x-1) y-5=6(x+1) y+1=6(x-5)
\(\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ -1}})\quad % (c,d) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies6 \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\)
@jdoe0001 what is the answer, I can't get it
All you need to do is plus in 5 and -1
@royalranger so want is the answer
@DoodleDuck8 ... @jdoe0001 posted the equation for "point-slope form" The question gives you a point & the slope (aka m) All you need to do is plug in the values into the point-slope form set up
And @DoodleDuck8 idk what is the answer? XD
@sunnnystrong Savage
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