Question

help please

Answer 1

@3mar

Answer 2

HI!!

Answer 3

The function continuous? Yes because it is a polynomial. Therefore you can differentiate.

Answer 4

what is \(f(-3)\)?

Answer 5

can you just show me all please ??? in one organized [ost?

Answer 6

Find the derivative and set it equal to
(f(1)-f(-3))/1-(-3)

Answer 7

you need to check first if \[f(-3)=f(1)\] if it is not,, then you

Answer 8

cannot use Rolles theorem

Answer 9

no its not fit

Answer 10

so D?? right?? ma

Answer 11

no actually i think they are equal
that is why my first question was, what is \(f(-3)\) ?

Answer 12

@misty1212 so what are you saying??

Answer 13

No, Rolles theorem can be applied. Just like i said in my first post. Therefore C and D are no longer options.

Answer 14

i am asking if you know what \(f(-3)\) is
that is all

Answer 15

sometimes A

Answer 16

what

Answer 17

@misty1212 He's all yours.

Answer 18

A?

Answer 19

hopefully \(f(-3)\) is a number, not a letter

Answer 20

??@misty1212

Answer 21

@misty1212

Answer 22

i don't know how else to ask the question
\[f(x)=x^2+2x-1\] the question is, what you need first, is to find \[f(-3)\]

Answer 23

@misty1212

Answer 24

A or B??

Answer 25

hint \[f(-3)=(-3)^2+2\times (-3)+1\]

Answer 26

A!

Answer 27

ur answer is b -1

Answer 28

\[f(-3)=A\]?? it is a number, not a letter

Answer 29

@iwanttogotostanford Your username says that you want to go to Stanford University, but you dont even want to do the work that will get you there. Most of the people here want to help, not do the work for you and give you the answer.

Answer 30

stop worrying about letters, or even the answer
you need to understand what the question is asking first
before you can begin, you need to find boty \(f(-3)\) and \(f(1)\)
if you cannot do that, you cannot proceed

Answer 31

yes @misty1212 is correct, u have understand the process, and the condition for rolle's
and why and how is works

Answer 32

Sorry, I was not online!
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