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please help what is this magic? \(\frac{dy}{dt} = (y+2)(y-1)\)
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@518nad
\(\frac{dy}{dt} = (y+2)(y-1)\)
\(\frac{dy}{dt} = y^2 + y -2\)
:) separate the weed from the good
no no it was fine the way it was before silly
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yeah, I got stuck at u sub u = y + 1/2
okay so put all the ys on one side with dy and dt on oone side
\(\frac{1}{(y+2)(y-1)} dy= 1 dt \)
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