(x2 + 3x + 4)(2x2 + 4x + 7)
hmmm oooooooooook
factor them out? set to zero and solve for x? multiply them? you need to be specific with what to do.
if you're asking on how to multiply them well, take each term on one, and multiply each term by the other then combine their results say for example \(\bf \begin{array}{llll} x^2 + 3x + 4 \\ \quad \\ \qquad \times \quad 2x^2 \\\hline\\ \square ?+\square ?+\square ? \end{array}\quad \begin{array}{llll} x^2 + 3x + 4 \\ \quad \\ \qquad \times \quad 4x \\\hline\\ \square ?+\square ?+\square ? \end{array}\quad \begin{array}{llll} x^2 + 3x + 4 \\ \quad \\ \qquad \times \quad 7 \\\hline\\ \square ?+\square ?+\square ? \end{array}\) then combine their results
\[(x^2+3x+4)(2x^2+4x+7)=2x^4+10x^3+27x^2+37x+28\] =
@yasmin .. yes what is the goal of this problem XD
Yasmin, the goal of the problem is to complete the indicated multiplication.
Multiply (x^2 + 3x + 4) by (2x^2 + 4x + 7), or vice versa. The first of the 3 terms in the first multiplicand is x^2. Multiply each of the 3 terms in the 2nd multiplicand by x^2. Next, by 3x. Next, by 4. Add all the resulting products together, combining like terms.
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