Question

What is an equation of the line that passes through (0, 8) and (4, 0)?

y = -2x + 4
y = 2x + 4
y = -2x + 8
y = 2x + 8

Answer 1

@AMQ

Answer 2

www.desmos.com

Answer 3

C

Answer 4

100% sure :p

Answer 5

Do you want to learn how to do it or cheat and fail math the rest of your life?

Answer 6

it's ok to rage when you don't get the medals green. there there..... *pats head*

Answer 7

I thought direct answers were illegal on this site...

Answer 8

nope

Answer 9

igreen with his paragraph of bull shi't VVVVVVVVVVVv

Answer 10

trust me on this ;)

Answer 11

To figure out the problem, find the slope of the two points.

(0, 8), (4, 0)
x1 y1 x2 y2

\(\sf \dfrac{y_2 - y_1}{x_2-x_1}\)

After you find the slope you plug it in with one of the points into point slope form.

\(\sf y - y_1 = m(x - x_1)\)

Where \(\sf m\) is the slope and \(\sf (x_1, y_1)\) is a point on the line.

Then you can convert it to slope-intercept form.

Answer 12

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