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Mathematics 17 Online
joshiscool:

Help me!

SkyVoltage43:

i has a question can you pm me

joshiscool:

@Parth

Parth:

hey sup

joshiscool:

http://prntscr.com/e5nwwd

Parth:

1, 2 are none of these 5, 6 are vertical

joshiscool:

i have more

joshiscool:

http://prntscr.com/e5ny4g

Parth:

3x - 25 = 6x - 80 cuz vertical angles are equal 3x = 55 x = 55/3

joshiscool:

http://prntscr.com/e5nyt3

Parth:

x + (3x+30) = 90

joshiscool:

thats not a option on there

joshiscool:

@MARC @Marziman

Parth:

solve the equation

joshiscool:

http://prntscr.com/e5o0ip

MARC:

Parth is right. \(x+(3x+30)=90\)

MARC:

\(4x+30=90\) Subtract both sides by 30

joshiscool:

but its not a option on the assignment

MARC:

\(4x+30-30=90-30\)

MARC:

\(4x=60\)

MARC:

div both sides by 4

MARC:

\(\frac{4}{4}x=\frac{60}{4}\)

joshiscool:

its 15

MARC:

yep,that's right!

joshiscool:

http://prntscr.com/e5o0ip

joshiscool:

http://prntscr.com/e5o3mh

joshiscool:

^ thats the one

MARC:

yep,that's right. \(z+43=180\)

MARC:

\(z=180-43\)

Marziman:

X = 15, Josh for an angle to be complementary the 2 need to add up and form a right angle so 3*15+30 = 75 then + angle 1 = 90

MARC:

\(z=137\)

joshiscool:

http://prntscr.com/e5o4fd

MARC:

corresponding angle \(\angle~s=\angle~u\)

MARC:

\(\angle~u+158=180\)

MARC:

\(\angle~u=22\)

MARC:

sub. the value of angle u into this eqn to find the value of angle s \(\angle~s=\angle~u\)

MARC:

\(\angle~s=?\)

joshiscool:

so do i subtract those?

MARC:

hmm,what do u mean?

MARC:

oh I c... sub.


> substitute

MARC:

sub. means substitute.

joshiscool:

Im lost on what to do

MARC:

which part u don't get it?

joshiscool:

<s

joshiscool:

^

ThewaffleBRO:

lol

joshiscool:

http://prntscr.com/e5o4fd

joshiscool:

@AMQ

AMQ:

im not sure, but i know that 158 is wrong

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