Question

[image]

Answer 1

lol

Answer 2

and i am now lost because i feel lazy

Answer 3

Get someone else

Answer 4

@mathmale

Answer 5

@sammixboo

Answer 6

Look carefully at the line. What is its y-intercept (vertical intercept)?
Next, figure out its slope. Need a reminder of what the slope formula is and how it works?

Answer 7

Ohh okieh yes please

Answer 8

Pick any 2 points on the line. I for one would choose the y-intercept and the x-intercept.
change in y
The slope formula, in words, is m = slope =

Answer 9

10 and 80? Or 0 and 100?

Answer 10

Hint: The y-intercept begins with 0: (0, ?). What is the y-value at which the line crosses the y-axis?

Answer 11

(0,100)?

Answer 12

I don't see your image; not sure why. Would it be possible to share it again?

Answer 13

Yeah

Answer 14

Is N=100 and M=0?

Answer 15

Or am I not even close? e.e

Answer 16

Actually, you've "nailed" the correct y-intercept. The y-intercept is the y-value when x=0. Thus, in this case, it's (0,100).

Please identify the x-value at the x-intercept.

Answer 17

0 is x.

Answer 18

The y-intercept is (0,100), as before, and yes, x = 0 at the y-intercept. Yes.

But I was asking you a new question. What are the coordinates of the x-intercept?
Look at the graph, where y=0. What is the x value where the line crosses the x-axis?

Answer 19

What? I don't understand what yer asking. You mean 45? e.e

Answer 20

Your graph is that of a straight line. It slants downward. It crosses the y-axis at (0,100).
We seem to agree on that.

Now I ask you to find the point where that same line crosses the x-axis. What are the coordinates of that point? No, not 45.

x = ? when y = 0

Answer 21

100

Answer 22

100 is the y-coordinate when x = 0.

When y = 0, x = 55.

Find the point (55,0) on the graph. Can you do that?

Answer 23

Um yes wait

Answer 24

In red.

Answer 25

Just look where the gray line crosses the horizontal (x-) axis and verify that the x-coordinate is 55. It is not 45 or 46. Delete that point in red, as it has no relevance to the question (what are the coordinates of the x-intercept?).

Answer 26

Oh my god. I don't know.

Answer 27

There

Answer 28

110? e.e

Answer 29

I can't see your text

Answer 30

I drew a graph but have not been able to share it with you yet.
Please look at the given graph once again.
Do you see a sloping gray line?

Answer 31

Yes the line across

Answer 32

There is only one sloping line in the diagram you've shared with me. That sloping line crosses both the vertical and the horizontal axes.

The point of intersection in the first case is (0,100).
The point of intersection in the second case is (55,0).

Look for these two points (they are not specifically marked).

Comfortable with this? or not?

Answer 33

Allison?

Answer 34

Uhh maybe? I think? e.e Sorry my mind is friend.
I see the 55 and 100 points.

Answer 35

Fried*

Answer 36

All right. You have 2 intercepts. One is (0,100) and the other is (55,0).
The 2 y-intercepts are 100 and 0 respectively; the 2 x-intercepts are 0 and 55.
Agree or disagree?

Answer 37

Yes what do I put as the answer though?

Answer 38

You need to find the slope of that sloping line.

Slope is (in words) rise over run.

Here the "rise" is actually a drop, since y=100 at x=0 and y=0 at x=55. Therefore, the "rise" is 0-100, or -100.

The "run" is 55-0, or 55.

So the slope is -100/55.

Think this through. We may have to continue with this later tonight, as I need to get off the 'Net in a minute or so.

Do you see how we obtained that slope, m = -100/55? Do you see how this reduces to m = -20/11?

Answer 39

Oh woeee e.e

Answer 40

So N = 11 + M = -20??

Answer 41

If you have the y-intercept and the slope, the equation of the line is
y=mx+b. Have you seen this formula before?

Answer 42

Yes

Answer 43

-.5 M+110 ???

Answer 44

Your slope is m=-20/11 and your y-intercept is b=100.

Therefore, your y=mx+b becomes y = (-20/11)x + 100.

Check this. Let x=55. If you obtain y=0, you'll know your equation is correct.

Sorry, Allison, but I need to excuse myself now. I'll be back in perhaps an hour.

Answer 45

Okay thanks and I won't be here in an hour..But thank yew :D

Answer 46

You're welcome!

Answer 47

Ohh the answer is N= -2 M + 110.

Answer 48

Your slope is m=-20/11 and your y-intercept is b=100.

Therefore, your y=mx+b becomes y = (-20/11)x + 100.

this is in the form y = mx + b.

Any questions? Note that this is very different from your n=-2m+110.

Answer 49

Oh..Well I submitted the test and it was N= -2 M + 110.