The functions q and r are defined as follows. q(x)=2x-1 r(x)=-2x^2+2 Find the value of q(r(−3))=
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Hrmmm I solved et and got du same answer o:
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first put -3 in place of x in function r(x)
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the value you get from this, you put in place of x in q(x)
working : \(=q[(r(-3)]\) \(=q[-2(\color{red}{-3})^2+2)]\) \(=q[-2(9)+2]\) \(=q(-18+2)\) \(=q(-16)\) \(=2(\color{blue}{-16})-1\) \(=-32-1\) \(=?\) solve it! @Hayhayz
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Hayzio just for the future, when you have a question like this where it combines q(x) and r(x), you just combine the functions. The X was replaced by -3 in r(x) and q(x) so in the functions you simply replace those X variables with -3. Ez Pz
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