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Mathematics 9 Online
rootbeer003:

help

rootbeer003:

http://prntscr.com/ec9088

satellite73:

nice glasses

satellite73:

that is a load

satellite73:

\[2x^2+10x=0\] factors since each term has a common factor of \(2x\) you get \[2x(x+5)=0\]

rootbeer003:

do i delete what i put?

satellite73:

set each factor equal to zero, get \[2x=0\iff x=0\] or \[x+5=0\iff x=-5\]

satellite73:

yes it is ridiculous to use the quadratic formula in this simple case

rootbeer003:

http://prntscr.com/ec91os

satellite73:

looks alot better especially since you get an actual answer

WillieXO:

Hi Satellite.. Nice bysicle XD Did the whole website lagged off or was it just me xD

satellite73:

i dunno i just got here myself

rootbeer003:

http://prntscr.com/ec91yg

WillieXO:

for this type use scatter plot and see if it is linear or non

satellite73:

successive differences means subtract

satellite73:

\[5-14=?\\ 2-5=?\\ 5-2=?\\ 15-5=?\]

WillieXO:

Or that.. LOL

rootbeer003:

http://prntscr.com/ec931r

satellite73:

no i made a typo last one should be \(14-5=9\)

rootbeer003:

kk

rootbeer003:

is that it?

satellite73:

oh and i forgot one

satellite73:

lets back up

rootbeer003:

ok

satellite73:

oh no i didn't sorry, those are the successive differences

rootbeer003:

thats all?

satellite73:

the pattern is clear -9 , -3, 3 , 9 that means it is a quadratic function

satellite73:

in fact it is \[f(x)=3x^2+2\] you can check it

satellite73:

i am not sure if you are supposed to know that or not

satellite73:

you could just say "it is quadratic"

rootbeer003:

http://prntscr.com/ec94oo

satellite73:

looks good enuf to me

rootbeer003:

http://prntscr.com/ec94z9

satellite73:

just do it

rootbeer003:

huh!

satellite73:

\[f(x)=-2x^4\\ f(-2)=-2(-2)^4\] for the first one don't be blond

satellite73:

and that is the hardest one \[f(0)=0\\ f(-1)=-2\\ f(1)=-2\] you can do the first and last ones

rootbeer003:

no i cant

satellite73:

then i guess you can't get this right

satellite73:

but of course you can probably even without a calculator, but surely with one you can compute \[-2\times (-2)^4\]

rootbeer003:

-32x

satellite73:

there is no x there

satellite73:

that was a times sign yo

rootbeer003:

http://www.wolframalpha.com/input/?i=-2+x+(-2)%5E4

satellite73:

so you have to plot the points \[(-2,-32), (-1,-2),(0,0),(1,-2),(2,-32)\]

rootbeer003:

http://prntscr.com/ec97f8 ok but this is what i have so far

satellite73:

put the numbers in the boxes

rootbeer003:

ok which numbers and in which box.

satellite73:

christ

satellite73:

the -32 goes in the box under the -2 etc

rootbeer003:

ok.. next

rootbeer003:

http://prntscr.com/ec98el

satellite73:

keep going

rootbeer003:

omg.

satellite73:

write the numbers in for the love of pete just do it

rootbeer003:

http://prntscr.com/ec98qh

rootbeer003:

?????????????

satellite73:

what about the last one?

rootbeer003:

-2??

satellite73:

it is wrong here \[(-2,-32), (-1,-2),(0,0),(1,-2),(2,-32)\] i did it for you put the second numbers under the first numbers

rootbeer003:

why couldnt u do that at first

rootbeer003:

oh u did

rootbeer003:

im dumb sorry

rootbeer003:

http://prntscr.com/ec9a3t

satellite73:

good

rootbeer003:

thats all?

satellite73:

connect the dots maybe does it as about end behaviour?

rootbeer003:

idk

satellite73:

read it

rootbeer003:

http://prntscr.com/ec9ayc

rootbeer003:

idk what thats means

satellite73:

where the curve is pointing as x goes to infinity and to minus infinity in both cases the curve goes down to minus infinity' that is the "end behaviour"

rootbeer003:

yea it does i think

rootbeer003:

http://prntscr.com/ec9bnt

satellite73:

don't connect the dots like that on the bottom

rootbeer003:

http://prntscr.com/ec9byo

satellite73:

ugly but better looks more like this http://www.wolframalpha.com/input/?i=-2x%5E4

rootbeer003:

k what do i do about end behavior thing?

satellite73:

read what i wrote above

rootbeer003:

i say that?

rootbeer003:

...?

satellite73:

or paraphrase it

rootbeer003:

no i think the question asks about our functions end behevior not the definition

satellite73:

say it goes to minus infinity that is all

rootbeer003:

http://prntscr.com/ec9dw7

satellite73:

looks good enuf

rootbeer003:

ok you know those questions i said nvm about and we dident do it? can we do it

satellite73:

if i can yes

rootbeer003:

http://prntscr.com/ec9evm

satellite73:

i cannot do that

satellite73:

plot points if you can

rootbeer003:

well i need to do it either now and get it done or later

rootbeer003:

why cant u do it?

satellite73:

too lazy it is your job not mine it is too small it is boring i don't know how to do it so you can see it whatever whatever plot the points, the year is on the horizontal axis, the population on the vertical axis so for example plot the point \((2000,1605)\)

rootbeer003:

oh thats easy, ill plot the points then what do u do next?

satellite73:

find the slope if you can

rootbeer003:

http://prntscr.com/ec9gmo

satellite73:

looks good

rootbeer003:

ok next

rootbeer003:

how to find slope?

satellite73:

i wish i knew

satellite73:

show me again the original problem

rootbeer003:

http://prntscr.com/ec9hjb

satellite73:

looks like an increase of 800 in 10 years, slope is \(\frac{800}{10}=80\) if i read it right

satellite73:

close enuf

rootbeer003:

http://prntscr.com/ec9i15

satellite73:

i would say "about"

rootbeer003:

ok dats it?

satellite73:

yup

satellite73:

unless htere is more

rootbeer003:

http://prntscr.com/ec9ij7

rootbeer003:

last one for tonight

satellite73:

\[x+y=5\\ .10x+.25y=1\] solve

rootbeer003:

umm x=7.5???

satellite73:

no

rootbeer003:

http://prntscr.com/ec9kdb

satellite73:

first one should be \(x+y=5\)

rootbeer003:

oh oops

rootbeer003:

looks good?

rootbeer003:

??

rootbeer003:

http://prntscr.com/ec9lbe

satellite73:

good

satellite73:

and good night

rootbeer003:

bye

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