Mathematics
9 Online
rootbeer003:
help
9 years ago
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satellite73:
nice glasses
9 years ago
satellite73:
that is a load
9 years ago
satellite73:
\[2x^2+10x=0\] factors since each term has a common factor of \(2x\) you get \[2x(x+5)=0\]
9 years ago
rootbeer003:
do i delete what i put?
9 years ago
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satellite73:
set each factor equal to zero, get \[2x=0\iff x=0\] or \[x+5=0\iff x=-5\]
9 years ago
satellite73:
yes it is ridiculous to use the quadratic formula in this simple case
9 years ago
satellite73:
looks alot better
especially since you get an actual answer
9 years ago
WillieXO:
Hi Satellite.. Nice bysicle XD
Did the whole website lagged off or was it just me xD
9 years ago
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satellite73:
i dunno i just got here myself
9 years ago
WillieXO:
for this type use scatter plot and see if it is linear or non
9 years ago
satellite73:
successive differences means subtract
9 years ago
satellite73:
\[5-14=?\\
2-5=?\\
5-2=?\\
15-5=?\]
9 years ago
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WillieXO:
Or that.. LOL
9 years ago
satellite73:
no i made a typo
last one should be \(14-5=9\)
9 years ago
rootbeer003:
kk
9 years ago
rootbeer003:
is that it?
9 years ago
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satellite73:
oh and i forgot one
9 years ago
satellite73:
lets back up
9 years ago
rootbeer003:
ok
9 years ago
satellite73:
oh no i didn't sorry, those are the successive differences
9 years ago
rootbeer003:
thats all?
9 years ago
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satellite73:
the pattern is clear -9 , -3, 3 , 9
that means it is a quadratic function
9 years ago
satellite73:
in fact it is \[f(x)=3x^2+2\] you can check it
9 years ago
satellite73:
i am not sure if you are supposed to know that or not
9 years ago
satellite73:
you could just say "it is quadratic"
9 years ago
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satellite73:
looks good enuf to me
9 years ago
satellite73:
just do it
9 years ago
rootbeer003:
huh!
9 years ago
satellite73:
\[f(x)=-2x^4\\
f(-2)=-2(-2)^4\] for the first one
don't be blond
9 years ago
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satellite73:
and that is the hardest one \[f(0)=0\\
f(-1)=-2\\
f(1)=-2\] you can do the first and last ones
9 years ago
rootbeer003:
no i cant
9 years ago
satellite73:
then i guess you can't get this right
9 years ago
satellite73:
but of course you can
probably even without a calculator, but surely with one you can compute \[-2\times (-2)^4\]
9 years ago
rootbeer003:
-32x
9 years ago
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satellite73:
there is no x there
9 years ago
satellite73:
that was a times sign yo
9 years ago
satellite73:
so you have to plot the points \[(-2,-32), (-1,-2),(0,0),(1,-2),(2,-32)\]
9 years ago
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satellite73:
put the numbers in the boxes
9 years ago
rootbeer003:
ok which numbers and in which box.
9 years ago
satellite73:
christ
9 years ago
satellite73:
the -32 goes in the box under the -2 etc
9 years ago
rootbeer003:
ok.. next
9 years ago
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satellite73:
keep going
9 years ago
rootbeer003:
omg.
9 years ago
satellite73:
write the numbers in for the love of pete
just do it
9 years ago
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rootbeer003:
?????????????
9 years ago
satellite73:
what about the last one?
9 years ago
rootbeer003:
-2??
9 years ago
satellite73:
it is wrong
here \[(-2,-32), (-1,-2),(0,0),(1,-2),(2,-32)\] i did it for you
put the second numbers under the first numbers
9 years ago
rootbeer003:
why couldnt u do that at first
9 years ago
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rootbeer003:
oh u did
9 years ago
rootbeer003:
im dumb sorry
9 years ago
satellite73:
good
9 years ago
rootbeer003:
thats all?
9 years ago
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satellite73:
connect the dots maybe
does it as about end behaviour?
9 years ago
rootbeer003:
idk
9 years ago
satellite73:
read it
9 years ago
rootbeer003:
idk what thats means
9 years ago
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satellite73:
where the curve is pointing as x goes to infinity and to minus infinity
in both cases the curve goes down to minus infinity'
that is the "end behaviour"
9 years ago
rootbeer003:
yea it does i think
9 years ago
satellite73:
don't connect the dots like that on the bottom
9 years ago
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rootbeer003:
k what do i do about end behavior thing?
9 years ago
satellite73:
read what i wrote above
9 years ago
rootbeer003:
i say that?
9 years ago
rootbeer003:
...?
9 years ago
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satellite73:
or paraphrase it
9 years ago
rootbeer003:
no i think the question asks about our functions end behevior not the definition
9 years ago
satellite73:
say it goes to minus infinity
that is all
9 years ago
satellite73:
looks good enuf
9 years ago
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rootbeer003:
ok you know those questions i said nvm about and we dident do it? can we do it
9 years ago
satellite73:
if i can yes
9 years ago
satellite73:
i cannot do that
9 years ago
satellite73:
plot points if you can
9 years ago
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rootbeer003:
well i need to do it either now and get it done or later
9 years ago
rootbeer003:
why cant u do it?
9 years ago
satellite73:
too lazy
it is your job not mine
it is too small
it is boring
i don't know how to do it so you can see it
whatever whatever
plot the points, the year is on the horizontal axis, the population on the vertical axis
so for example plot the point \((2000,1605)\)
9 years ago
rootbeer003:
oh thats easy, ill plot the points then what do u do next?
9 years ago
satellite73:
find the slope if you can
9 years ago
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satellite73:
looks good
9 years ago
rootbeer003:
ok next
9 years ago
rootbeer003:
how to find slope?
9 years ago
satellite73:
i wish i knew
9 years ago
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satellite73:
show me again the original problem
9 years ago
satellite73:
looks like an increase of 800 in 10 years, slope is \(\frac{800}{10}=80\) if i read it right
9 years ago
satellite73:
close enuf
9 years ago
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satellite73:
i would say "about"
9 years ago
rootbeer003:
ok dats it?
9 years ago
satellite73:
yup
9 years ago
satellite73:
unless htere is more
9 years ago
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rootbeer003:
last one for tonight
9 years ago
satellite73:
\[x+y=5\\
.10x+.25y=1\] solve
9 years ago
rootbeer003:
umm x=7.5???
9 years ago
satellite73:
no
9 years ago
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satellite73:
first one should be \(x+y=5\)
9 years ago
rootbeer003:
oh oops
9 years ago
rootbeer003:
looks good?
9 years ago
rootbeer003:
??
9 years ago
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satellite73:
good
9 years ago
satellite73:
and good night
9 years ago
rootbeer003:
bye
9 years ago