Mathematics
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rootbeer003:
help
9 years ago
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HuskyNation:
yes?
9 years ago
rootbeer003:
Wheres @satellite73
9 years ago
HuskyNation:
i can help to but i guess i am not welcomed
9 years ago
rootbeer003:
Eh its hard work
9 years ago
satellite73:
on vacation
9 years ago
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rootbeer003:
AYE
9 years ago
rootbeer003:
we gotta do that one u dont like
9 years ago
rootbeer003:
the one we left for last
9 years ago
HuskyNation:
let's post it and let me see
9 years ago
satellite73:
yeah it is a kind of DIY problem
9 years ago
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rootbeer003:
u think if u cant do it i can
9 years ago
rootbeer003:
u got jokes
9 years ago
HuskyNation:
lol satellite. post it i wanna see
9 years ago
rootbeer003:
llol u ok?
9 years ago
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HuskyNation:
give me a sec to try and solve it, i do it on paper
9 years ago
rootbeer003:
ok
9 years ago
satellite73:
how's it going?
9 years ago
rootbeer003:
Good
9 years ago
HuskyNation:
A) c(x) = x^2+4x-5/(x+5) would be undefined at x = -5 because the denominator = 0 (zero) , which means it is undefined.
9 years ago
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satellite73:
so for a) identify the restricted domain you say "all real numbers except \(-5\)"
9 years ago
HuskyNation:
seems right @satellite73 ?
9 years ago
satellite73:
yes it is right
9 years ago
HuskyNation:
thank you
9 years ago
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satellite73:
then factor and cancel
9 years ago
rootbeer003:
ok next
9 years ago
satellite73:
next is part B
factor the numerator, then cancel the common factor of \(x+5\)
9 years ago
HuskyNation:
Now let's simplify c(x). The numerator factors to (x+5)(x-1)
c(x) = x^2+4x-5/(x+5) = (x+5)(x-1)/(x+5) = x-1
9 years ago
HuskyNation:
right?
9 years ago
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satellite73:
yes right
you end up with only \(x-1\)
9 years ago
HuskyNation:
and for c) just graph it: The graph of x-1 is a straight line with a slope of 1 and y-intercept of -1. Place a small circle on the line at x=-5 to indicate that no value is defined for c(x) at this point.
9 years ago
satellite73:
yup
then graph the line \(y=x-1\) except put a whole where \((-5,-6)\) should be
9 years ago
HuskyNation:
hole* ;)
9 years ago
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rootbeer003:
juicey?
9 years ago
satellite73:
you need to graph the line dear
9 years ago
rootbeer003:
??????
9 years ago
HuskyNation:
mhmm
9 years ago
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satellite73:
plot some points, connect the dots
say \((0,-1)\), \((2,1)\) and \((4,3)\)
ought to be enough
you just put a dot down, you need a line
9 years ago
satellite73:
|dw:1489111621232:dw|
9 years ago
satellite73:
better
much better
guess they don't allow pencils where you are huh?
9 years ago
rootbeer003:
actually this looks cooler
9 years ago
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satellite73:
i agree
good work
9 years ago
HuskyNation:
@satellite73 it was an honor to work with you
9 years ago
satellite73:
pleasure is mine @HuskyNation
9 years ago
wo1f0mon:
good job satellite
9 years ago
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rootbeer003:
lol
9 years ago
satellite73:
ok fine
vertical asymptote set the denominator equal to zero solve for x (in your head)
what do you get ?
9 years ago
satellite73:
...
9 years ago
rootbeer003:
gtg
9 years ago
HuskyNation:
well then
9 years ago
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satellite73:
ciao for now
9 years ago
HuskyNation:
i always looked up to you @satellite73 in OpenStudy, my username was Oregonduck if u rememeber
9 years ago
satellite73:
hi, nice to see you again!
go ducks!!
9 years ago
HuskyNation:
x'D thank like wise :D
9 years ago
Allison:
If this question has been answered, please close it. Thank you! :)
9 years ago
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HuskyNation:
how did u get 2 medals ally O.O
9 years ago