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Mathematics 16 Online
rootbeer003:

help

HuskyNation:

yes?

rootbeer003:

Wheres @satellite73

HuskyNation:

i can help to but i guess i am not welcomed

rootbeer003:

Eh its hard work

satellite73:

on vacation

rootbeer003:

AYE

rootbeer003:

we gotta do that one u dont like

rootbeer003:

the one we left for last

HuskyNation:

let's post it and let me see

satellite73:

yeah it is a kind of DIY problem

rootbeer003:

u think if u cant do it i can

rootbeer003:

u got jokes

HuskyNation:

lol satellite. post it i wanna see

rootbeer003:

http://prntscr.com/ei3adz

rootbeer003:

llol u ok?

HuskyNation:

give me a sec to try and solve it, i do it on paper

rootbeer003:

ok

satellite73:

how's it going?

rootbeer003:

Good

HuskyNation:

A) c(x) = x^2+4x-5/(x+5) would be undefined at x = -5 because the denominator = 0 (zero) , which means it is undefined.

satellite73:

so for a) identify the restricted domain you say "all real numbers except \(-5\)"

HuskyNation:

seems right @satellite73 ?

rootbeer003:

http://prntscr.com/ei3cwp

satellite73:

yes it is right

HuskyNation:

thank you

satellite73:

then factor and cancel

rootbeer003:

ok next

satellite73:

next is part B factor the numerator, then cancel the common factor of \(x+5\)

HuskyNation:

Now let's simplify c(x). The numerator factors to (x+5)(x-1) c(x) = x^2+4x-5/(x+5) = (x+5)(x-1)/(x+5) = x-1

HuskyNation:

right?

satellite73:

yes right you end up with only \(x-1\)

rootbeer003:

http://prntscr.com/ei3dy8

HuskyNation:

and for c) just graph it: The graph of x-1 is a straight line with a slope of 1 and y-intercept of -1. Place a small circle on the line at x=-5 to indicate that no value is defined for c(x) at this point.

satellite73:

yup then graph the line \(y=x-1\) except put a whole where \((-5,-6)\) should be

HuskyNation:

hole* ;)

rootbeer003:

http://prntscr.com/ei3efp

rootbeer003:

juicey?

satellite73:

you need to graph the line dear

rootbeer003:

??????

HuskyNation:

mhmm

satellite73:

plot some points, connect the dots say \((0,-1)\), \((2,1)\) and \((4,3)\) ought to be enough you just put a dot down, you need a line

satellite73:

|dw:1489111621232:dw|

rootbeer003:

http://prntscr.com/ei3f3x

satellite73:

better much better guess they don't allow pencils where you are huh?

rootbeer003:

actually this looks cooler

satellite73:

i agree good work

HuskyNation:

@satellite73 it was an honor to work with you

satellite73:

pleasure is mine @HuskyNation

wo1f0mon:

good job satellite

rootbeer003:

http://prntscr.com/ei3fk9 WE AINT DONE HERE

rootbeer003:

lol

satellite73:

ok fine vertical asymptote set the denominator equal to zero solve for x (in your head) what do you get ?

satellite73:

...

rootbeer003:

gtg

HuskyNation:

well then

satellite73:

ciao for now

HuskyNation:

i always looked up to you @satellite73 in OpenStudy, my username was Oregonduck if u rememeber

satellite73:

hi, nice to see you again! go ducks!!

HuskyNation:

x'D thank like wise :D

Allison:

If this question has been answered, please close it. Thank you! :)

HuskyNation:

how did u get 2 medals ally O.O

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