help
@satellite73
if you put \(x\) equal the hours, and \(y\) as the cost, then at the current rate the cost in terms of hours is \[y=4x+6\] at the increased rate it would be \[y=5x+10\]
mk
for 6 hours at the current rate it would cost \[y=4\times 6+6=24+6=60\] so \(\$30\) at the increased rate it would be \[y=5\times 6+10=30+10=40\] so \(\$40\)
ok
is that a and b
yes, A and B both parts
ok
C increase from \(\$30\) to \(\$40\) is \(\$10\) as a percent of the original cost \(10\div30=\frac{1}{3}=33\tfrac{1}{3}\%\)
that was C in case you were wondering
mhm
D if he paid \(\$42\) the original rate, you have \[4x+6=42\] subtract 6 get \[4x=36\] divide by 4 get \[x=9\] he rode for nine hours
that was D
Ok next?
\[3x+5y=-9\\ 2x+y=-34\] substitution might be easiest the second equation \(2x+y=-34\) is the same as \(y=-2x-34\) substitute that in the first equation for \(y\) get \[3x+5(-2x-34)=-9\]
to solve that, first distribute \[3x-10x-170=-9\] combine like terms get \[-7x-170=-9\] add \(170\) get \(-7x=161\) divide by \(-7\) get \(x=-23\)
then substitute \(x=-23\) in either of the original equations, for example in \[y=-2x-34\] get \[y=-2\times 23-34=12\] so the solution is \[x=-23,y=12\] or as an ordered pair \[(-23,12)\]
ok
typo there, should be \[y=-2\times (-23)-34=12\]
i hope you have some part before that, like how you got the \(x=-23\)
lol
looks good?
yes, looks excellent, since i wrote it
ya
ok graph now?
what shall i do
graph it, i can't do it for you you have two lines to graph you have to do it. i can help, hold on one second i have to answer an email
can i use desmo graph
or u can tell me what it suposed to look like
you can use desmos
the two lines will intersect at \((-23,12)\)
okie dokie
wait what do i type into desmo
i don't know, i never use it
ok then on wolf
i did it, it worked fine
in demsos type in \[3x+5y=-9\] on the upper left, then go to the next box down and type in \[2x+y=-34\]
mine should look exaclty like dat
scroll in so that it goes from -36 to 36 like your graph paper make sure they intersect at the point \((-23,12)\) yes, it should look like dat
dont have to be perf
put \(x\) as the amount of money at the movie theater , and \(y\) as the amount of money at the pet store then the first equation is \[10x+8y=152.50\] and the second is \[8x+12y=171\]
how does my graph look
ugly the lines are supposed to be straight
no one perfect
no, that is for sure
lol but they are OKAY?
yes good enuf
ok is that all for the 2nd one?
yes
hold the phone
we are not done with the pet store
o okkkkk
well i asked
\[10x+12y=152.50\\ 8x+12y=171\] we need so solve
typo \[10x+8y=152.50\\ 8x+12y=171\]
multiply the first equation by \(-3\) and the second equation by (2\) and you get \[-30x-24y=-457.50\\ 16x+24y=242\]
I hope there arnt from yahoo answers. i could get in trouble
i think i made a mistake somewhere
ARE they?
are they what?
Are these answers of yahoo answers?
off
lol hell no here solve \[10x+8y=152.50\\ 8x+12y=171\] you get \[x=8.25, y=8. 75\] so \(\$8.25\) at the movies, \(\$8.75\) at the pet store
don't ask how to solve it, i used wolfram next...
make a new thread
is that it for this one?
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