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Mathematics 13 Online
rootbeer003:

Help

satellite73:

with?

rootbeer003:

algebra 2 part 2

satellite73:

oh be still my heart

rootbeer003:

next is pre calculus

rootbeer003:

ok but can u actually help me understand the stuff u help me wwith unless were in a hurry?

satellite73:

then trig then calc then calc two then differential equations calc three linear algebra

satellite73:

no hurry

satellite73:

let me get a pretzel and a drink of water, go ahead and post

rootbeer003:

same

satellite73:

back

rootbeer003:

http://prntscr.com/emwrov

satellite73:

that is not algebra, that is arithmetic

rootbeer003:

whats that.

satellite73:

you know, stuff with numbers instead of variables do you know how to do long division?

satellite73:

i hope so because it is impossible to write long division here

rootbeer003:

um i use mathway

satellite73:

well i can just tell you that the remainder is 6, because \[9712=211\times 46+\color{red}6\]

rootbeer003:

ok so im right

rootbeer003:

if im right u dont need to explain

satellite73:

you know how to set up a long division problem? yes, you are always right

rootbeer003:

http://prntscr.com/emwteq

satellite73:

right again

rootbeer003:

http://prntscr.com/emwtva

rootbeer003:

idk

satellite73:

ok so now we learn something

satellite73:

thank god that ugly guy left' in any case you have to factor, because that is what is says to do

rootbeer003:

ok

satellite73:

we got \[x^2-3x-28=0\] and we want to factor it do you know what that means?

rootbeer003:

put on the x's and one with no x's together

rootbeer003:

idk

satellite73:

it meant to write it as a product , like \[(x+5)(x-4)\] or something like that that is not the answer, that is just what it will look like

rootbeer003:

how do i put it like that

satellite73:

you first have to think of two numbers that multiply to get \(-28\) pretty clearly one has to be positive and one has to be negative can you think of two numbers that whose product is \(-28\)?

rootbeer003:

um

rootbeer003:

4 x -7

satellite73:

try i can tell you one, \(-1\) and \(28\) since \(-1\times 28=-28\) see if you can... ok got it

satellite73:

now we are not done yet, you have to check if \[4+(-7)=-3\] which is does

satellite73:

that means \[x^2-3x-28=(x+4)(x-7)\] if \[(x+4)(x-7)=0\] then either \[x+4=0\] so \[x=-4\] or \[x-7=0\] so \[x=7\]

rootbeer003:

then c or a

satellite73:

your two answers are therefore \[\{7,-4\}\]

satellite73:

no not C or A, only C has that pair

rootbeer003:

not c but its c??

satellite73:

it is C, yes

rootbeer003:

http://prntscr.com/emwwt2

satellite73:

as x goes to infinity, that means x is going to the right it should be clear from your eyeballs that as x goes to the right, the curve is headed downward to as x goes to infininity, f goes to \(-\infty\)

satellite73:

oh they right it in words as x goes to infinity, \(f(x)\) goes to minus infinity and as x goes to minus infinity (you are headed to the left) the curve is going up so as x goes to minus infinity, \(f\) goes to plus infinity

rootbeer003:

so confusing

satellite73:

|dw:1490146845768:dw|

satellite73:

so as x goes to the right, \(f(x)\) is going down i.e. as \(x\) goes to infinity, \(f(x)\) goes to minus infinity

satellite73:

|dw:1490146952187:dw|

rootbeer003:

do u mean negative infinity?

satellite73:

so as x goes to minus infinity \(f(x)\) goes to plus infinity

satellite73:

minus infinity, negative infinity, same thing

rootbeer003:

d?

satellite73:

C

satellite73:

make a new thread, scrolling down is a pain

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