Help
with?
algebra 2 part 2
oh be still my heart
next is pre calculus
ok but can u actually help me understand the stuff u help me wwith unless were in a hurry?
then trig then calc then calc two then differential equations calc three linear algebra
no hurry
let me get a pretzel and a drink of water, go ahead and post
same
back
that is not algebra, that is arithmetic
whats that.
you know, stuff with numbers instead of variables do you know how to do long division?
i hope so because it is impossible to write long division here
um i use mathway
well i can just tell you that the remainder is 6, because \[9712=211\times 46+\color{red}6\]
ok so im right
if im right u dont need to explain
you know how to set up a long division problem? yes, you are always right
right again
idk
ok so now we learn something
thank god that ugly guy left' in any case you have to factor, because that is what is says to do
ok
we got \[x^2-3x-28=0\] and we want to factor it do you know what that means?
put on the x's and one with no x's together
idk
it meant to write it as a product , like \[(x+5)(x-4)\] or something like that that is not the answer, that is just what it will look like
how do i put it like that
you first have to think of two numbers that multiply to get \(-28\) pretty clearly one has to be positive and one has to be negative can you think of two numbers that whose product is \(-28\)?
um
4 x -7
try i can tell you one, \(-1\) and \(28\) since \(-1\times 28=-28\) see if you can... ok got it
now we are not done yet, you have to check if \[4+(-7)=-3\] which is does
that means \[x^2-3x-28=(x+4)(x-7)\] if \[(x+4)(x-7)=0\] then either \[x+4=0\] so \[x=-4\] or \[x-7=0\] so \[x=7\]
then c or a
your two answers are therefore \[\{7,-4\}\]
no not C or A, only C has that pair
not c but its c??
it is C, yes
as x goes to infinity, that means x is going to the right it should be clear from your eyeballs that as x goes to the right, the curve is headed downward to as x goes to infininity, f goes to \(-\infty\)
oh they right it in words as x goes to infinity, \(f(x)\) goes to minus infinity and as x goes to minus infinity (you are headed to the left) the curve is going up so as x goes to minus infinity, \(f\) goes to plus infinity
so confusing
|dw:1490146845768:dw|
so as x goes to the right, \(f(x)\) is going down i.e. as \(x\) goes to infinity, \(f(x)\) goes to minus infinity
|dw:1490146952187:dw|
do u mean negative infinity?
so as x goes to minus infinity \(f(x)\) goes to plus infinity
minus infinity, negative infinity, same thing
d?
C
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