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NvidiaIntely:
How do I find the value of H in a function?
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SkyVoltage43:
you cant cause H isnt in function lol
NvidiaIntely:
Here:
SkyVoltage43:
i still dont see H but i see x
NvidiaIntely:
But the question is H :/
SkyVoltage43:
and?
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NvidiaIntely:
It says "What is the value of h in the function?".
SkyVoltage43:
but H isnt in the equation
NvidiaIntely:
Yeah.
So now what? LOL
SkyVoltage43:
lol idk find an H and add it ig or just give up on life
SkyVoltage43:
@Warriorz13
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NvidiaIntely:
Okay then how do I find the value of X?
cloudberry:
Open the brackets..
NvidiaIntely:
What does that mean?
cloudberry:
\[\frac{1}{2}\times(x^{2}+10x+25)-9\]
trueangel12312:
Any answer choices?
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NvidiaIntely:
Yes:
5
1/2
9
-5
trueangel12312:
Oh okay thanks
Nnesha:
h is the x-coordinate of the vertex
Nnesha:
\[f(x)=a(x-h)^2+k\] if the equation is written in vertex form
(h,k) represent the vertex
what number is replaced by `h` in your equation ?
Nnesha:
\[y=a(x+h)^2+k\] if it's `+h` then the x-coordinate of the vertex would be negative
x-coordinate of vertex=-h
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NvidiaIntely:
So its -5?
Nnesha:
yes
NvidiaIntely:
Thanks Nnesha!
Nnesha:
yw
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