Katrina rolls a pair of six-sided number cubes with numbers 1 to 6. What is the probability that the sum of the numbers rolled is either an even number or a multiple of 3?
@Hero
i'm getting vibes that its 1/2, but realized that i also need the multiples of 3, so 3 + 2 is 5/6 and reduced is 3/2, which we should put it at 2/3. that right? @Hero
There is a correct approach to this. What I'm curious to know is, are you aware of what that approach is and can you explain the steps of how to properly set up and solve this.
well its a six-die so the denominator currently is 6 so it wants an even or a multiple of 3, theres 3 even numbers and 2 multiples, counting six itself so thats 5 5/6
if we dont count six, then 4/6 which is still 2/3
The first step is to figure out the total possible outcomes. In other words how many total rolled-dice sums are possible?
6
there are six outcomes, which is all the numbers it can be
Actually, you have to count pairs of numbers. For example, You could roll two 1's, two 2's, two 3's, two 4's, two 5's and two 6's. That's six outcomes right there but that obviously isn't the total number of outcomes, because you can also roll a 2 and a 4 which would make it 7 outcomes we've listed so far.
wait, a pair? i thought it was one die
Katrina rolls a pair ....
shut up i didnt see that!
...
so we have about 12 outcomes
which is 10 / 12 now
5/6 is half of it
...
still seems like its 2/3....
There's more than 12 outcomes
then im stumped
There's 36 outcomes actually. I'm not going to list them all. But it goes something like (1,1), (1,2), (1,3), (1,4),(1,5),(1,6) (2,1), (2,2), (2,3), (2,4), (2,5), (2,6) ... (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
18 even numbers
plus 12 multiples of 3
very good
18 + 12 30
30/36
Good, now reduce that fraction.
5/6
Correct
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