Question

Can someone show me how to do these step by step I have a dba coming up

Answer 1

@Ultrilliam @YoursTruly @UsArmy3947 @Allison @Aeon @Amythehedgehog @Eiwoh2 @Elsa213 @elektroflow @Kakarot @katiebug2000

Answer 2

Tag Hero when he's online if you don't need this ASAP. But I think Howie or Nick can help you too.

Answer 3

@JustSaiyan @eiwoh2

Answer 4

ok

Answer 5

Were any of you online roughly 40 minutes ago, when I stated I needed an Algebra tutor? I am a Science and History guy. Not math. I recommend Evl and Hero for that.

Answer 6

Ok

Answer 7

@EvL @Warriorz13 @psirockin2

Answer 8

Um... As someone who is barely passing math, you might not want me here. Sorry

Answer 9

Oh phuck no ;-;
Sorry hun, Math scares me

Answer 10

It's ok and ok

Answer 11

Eiwoh probably knows how to solve it. o:

Answer 12

Elsa... what the heck are you voluntelling Howie for? He's too fragile for this

Answer 13

Howie is smart. He knows stuffz e.e

Answer 14

Maybe Aeon could help. e.e

Answer 15

Have you tried google yet, @ThisGirlPretty ? c:

Answer 16

No D:, I'm not good with math it takes me forever to learn it

Answer 17

Hero is good at explaining things. Maybe for a little bit for his lunch break. He's probably eating an Avocado sandwich *^*

Answer 18

And drinking his Mountain Spring Valley water cx

Answer 19

Sounds yummy and that's good :D I need someone to explain it to me because my math teacher wants me too or I would get extra credit D:

Answer 20

His lifestyle, Nick.

Answer 21

Welcome to QuestionCove, @ThisGirlPretty . o;

Answer 22

@Elsa213 Thank you :D

Answer 23

Oops Sorry I wasnt on >^<

Answer 24

First check if there is any common factor in the equation. Take out the common factor. There are different ways to factor the quadratic equation. The headphone method or factor by grouping (both are pretty much the same). Factoring will be easier if the leading coefficient is one \[\rm Ax^2+Bx+C=0\]
^the quadratic equation where
`A` is the leading coefficient
`B` the coefficient of middle term( x -term)
`C` Constant
Find two numbers that multiply to `AC` and add up to `B`
the factors will be (x+ 1st number)(x+ 2nd number)

Answer 25

The restriction: We can't divide by zero. To find the restriction on variable, set the denominator equal to zero and solve for the variable. (make sure you simplify the functions first)

Answer 26

tag me whenever you're free
we can solve first question together

Answer 27

the*

Answer 28

\[\large\rm Q1: \frac{ v^2-5v-14 }{ v^2+4v+4 }\]
lets factor the numerator first.
v^2 is same as 1v^2

\[\rm 1v^2-5v+14\]
what is the leading coefficient ??
what is B?
what number represent the constant term ?

Answer 29

Idk >_<

Answer 30

I know you have to factor it but i dont know how to factor these types

Answer 31

\[\large\rm \color{ReD}{A}x^2+\color{blue}{B}x+ \color{orange}{C}\]\[\large\rm \color{ReD}{1}x^2\color{blue}{-5}x+ \color{orange}{14}\]
A is the leading coefficient. so what number is replaced by A??

Answer 32

2?

Answer 33

we are working on this equation \[\large\rm \color{Red}{1}v^2\color{blue}{-5}v+\color{orange}{14}\]

Answer 34

1?

Answer 35

yes correct. and what's C and B?

Answer 36

5 and 14?

Answer 37

-5 for B
and yes 14 for C

Answer 38

now we have to find two numbers who multiply to AC( 1 times 14=14) which is 14
and add up to -5

Answer 39

A times C is 14

Answer 40

so what two numbers you should multiply to get 14 but when you add the same numbers you should get -5 ?

Answer 41

I know to get 14 is 2 and 7

Answer 42

opps sorry 14 is negative my bad

Answer 43

its ok

Answer 44

so which number should be negative ??(because we need -14 and -5)

Answer 45

7?

Answer 46

7?

Answer 47

7?

Answer 48

yes right so the factor for the numerator are (v +1st number )(v+ 2nd number)
(v-7)(v+2)
now factor the denominator.

Answer 49

\[\large\rm \color{red}{1}v^2+\color{blue}{4}v+\color{orange}{4} \]
a=?
b=?
c=?

Answer 50

idk :?

Answer 51

the number in front of the variable `v^2` is the leading coefficient
the number with no variable known as constant(C)
The number with the `x-term` represent the B value

Answer 52

I got it Can you give me an example of a vertical asymptote?

Answer 53

Vertical asymptote is same as finding the restriction on variable. Set the denominator equal to zero and solve for the variable.
for example \[\rm \frac{2x+9}{3x+4}\]
\[\rm VA~~~3x+4=0\]

solve for x \[\rm VA~~~x=-\frac{4}{3}\]

Answer 54

Ok one second

Answer 55

Hey @Nnesha Can you give me one example of oblique asymptote please

Answer 56

For oblique asymptote first make sure the numerator has highest power than the denominator
the oblique asymptote will be in linear equation form `y=mx+b`
are you familiar with long division ?? or synthetic division ?

Answer 57

if the function is \[\rm \frac{2x^2+9}{3x+4}\]
highest degree at the numerator is 2 which is greater than the highest degree for the function in the denominator
divide the function by using long division. The quotient will be the oblique asymptote.
I am not sure if you are familiar with long or synthetic division. you will not be able to find oblique asymptote Without knowing how to divide the polynomials.

Answer 58

Wait what is there isn't a degree higher than the numerator?

Answer 59

the degree is the exponent
2x^2+9 highest degree is 2
3x+4 highest degree is one