Question

can someone help me?

Answer 1

The standard form of the equation of a circle is (x−5)2+(y−6)2=1.



What is the general form of the equation?

x2+y2+10x+12y+62=0

x2+y2−10x−12y−62=0

x2+y2−10x−12y+60=0

x2+y2+10x+12y+60=0

Answer 2

@JustSaiyan

Answer 3

@Ultrilliam

Answer 4

Give me a second.

Answer 5

It would be C.

Answer 6

I can't answer this. I hate Algebra and all that it represents. I do Biology, History, Chemistry, Anything Science, and Translations. Not Math.

Answer 7

oh, well zowie can you answer some more?

Answer 8

I can try. :)

Answer 9

The center of a circle is located at (−2, 7) . The radius of the circle is 2.



What is the equation of the circle in general form?

x2+y2−4x+14y+51=0

x2+y2+4x−14y+49=0

x2+y2−4x+14y+49=0

x2+y2+4x−14y+51=0

Answer 10

It would be B. XD

Answer 11

The general form of the equation of a circle is x2+y2−4x−8y−5=0.



What are the coordinates of the center of the circle?

Answer 12

The center is (2,4)

Answer 13

What is the equation of this circle in general form?

x2+y2−2x−6y−26=0

x2+y2+2x+6y−26=0

x2+y2−2x−6y+4=0

x² + y² + 2x + 6y + 4 = 0

Answer 14

https://static.k12.com/nextgen_media/assets/8097093-NG_GMT_W_01_U12_Quiz_06.png

Answer 15

It would be A.

Answer 16

thank you for your help!