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Circle D has a radius of 21 millimeters and central angle, ∠EDF, which measures 60°. Find the exact length of arc EF
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I got 7pi
*7pi mm
@Oneofus are you planning to post the image that goes with this problem?
There is no imagine included @Hero
Okay, I assumed there was but I guess we don't need one for this problem.
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|dw:1494949746001:dw|
|dw:1494949898154:dw|
So for this we use the formula \(S = r\theta\) where S is the arc length in question, which in this case is EF. So, you input \(r = 21\) and \(theta = \dfrac{\pi}{3}\) since in the previous problem we figured out that \(60^{\circ}\) in radians is \(\dfrac{\pi}{3}\): \(S_{EF} = 21 \times \dfrac{\pi}{3}\)
So \(7\pi\) mm is correct.
Thank you!
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You're welcome.
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