Question

http://prntscr.com/fbtqw3

Answer 1

@Nnesha Can you show me the stops for solving for this problem?

Answer 2

steps*

Answer 3

first apply the distributive property:
\[\huge \rm \color{Red}{x}(y-z)=\color{Red}{x}(y) -\color{Red}{x}(z) \]
multiply all the terms inside the parentheses by outter number/varaible

Answer 4

\[\large \rm \color{Red}{x}(y-z)=\color{Red}{x}\cdot y -\color{Red}{x}\cdot z \]

Answer 5

do that part first

Answer 6

Oh, I had divided by a first

Answer 7

ab - ac = d is what I get after following your step

Answer 8

did you divide by a first ??

Answer 9

that works too

Answer 10

\[\large \rm ab-ac = d \]
we have to solve for `c` therefore we need to move everything else to the other side.
ab is positive at left side. in order to cancel out ab from left side we should subtract `ab` both sides
\[\large \rm \color{Red}{-ab}+ ab-ac = d\color{ReD}{-ab} \]

Answer 11

I got -ac = d - ab

Answer 12

yes how would you cancel out `-a` from left side ?

Answer 13

divide by -a?

Answer 14

yes

Answer 15

got it ? :)

Answer 16

uuh

Answer 17

-ac = d - ab

c = (d/-a) + (-ab/-a)

Answer 18

is that right

Answer 19

yes right negative/negative is positive
so c=-d/a+ab/a

Answer 20

and then if we combine the fractions, we get

(ab -d)/a

Right?

Answer 21

yes good!

Answer 22

haha thank you

Answer 23

can you help me with another one?

Answer 24

yw o^_^o

Answer 25

hmm

Answer 26

its too late here.. i need to zzz. i have a class tomorrow at 8 so..>_< sorry

Answer 27

its ok good night