Mathematics
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rootbeer003:
help
8 years ago
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rootbeer003:
8 years ago
satellite73:
a)list all factors of 18, don't forget the \(\pm\)
8 years ago
rootbeer003:
i put that?
8 years ago
satellite73:
no, you do that !!
8 years ago
rootbeer003:
u wont help
8 years ago
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rootbeer003:
k lets see
8 years ago
rootbeer003:
i dont get it
8 years ago
satellite73:
what numbers go in to 18 evenly?
8 years ago
rootbeer003:
2, 3, 6, 9
8 years ago
satellite73:
also 1 and 18
8 years ago
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rootbeer003:
kk
8 years ago
satellite73:
and like i said, don't forget the \(\pm\)
in front of each
8 years ago
satellite73:
do you know how to do synthetic division? it is real easy, but very hard to write here
8 years ago
rootbeer003:
8 years ago
rootbeer003:
lemme look it up
8 years ago
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satellite73:
ok
your answer there is good
8 years ago
rootbeer003:
looks confusing.. but go on
8 years ago
satellite73:
\[~~1~~-3~~-7~~15~~18\]
8 years ago
satellite73:
that is a list of the coefficients
since you are dividing by \(x-3\) you put a \(3\) on the side \[
8 years ago
satellite73:
\[~~1~~-3~~-7~~15~~18\\3\]
8 years ago
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satellite73:
then you drop down the 1
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3\\
~~~1\]
8 years ago
rootbeer003:
8 years ago
satellite73:
ok but you do not need that line above, the answer will be below
3 times 1 is 3
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~\\
~~~1\]
8 years ago
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rootbeer003:
8 years ago
satellite73:
that didn't work, let me try again
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~3\\
~~~1\]
8 years ago
satellite73:
one more time
8 years ago
rootbeer003:
cant u draw it
8 years ago
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satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~~~3\\
~~~1\]
8 years ago
satellite73:
that second 3 should go under the -3
8 years ago
satellite73:
then \(-3+3=0\)
8 years ago
rootbeer003:
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~~~~~3\\
~~~1~~~~0\]
8 years ago
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satellite73:
you need three rows all together
write it like i am trying to write it
8 years ago
rootbeer003:
kk
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~~~~~3~~~~~~0\\
~~~1~~~~0~~~~~~-7\]
8 years ago
rootbeer003:
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~~~~~3~~~~~~0~~~~-21\\
~~~1~~~~0~~~~~-7~~~~-6\]
8 years ago
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satellite73:
your 1 should be on the bottom row, one more line and we are done
8 years ago
rootbeer003:
what about between 1 and 1?
8 years ago
rootbeer003:
8 years ago
rootbeer003:
?
8 years ago
satellite73:
\[~~~1~~-3~~-7~~15~~18\\
3~~~~~~3~~~~~~0~~~-21~~~-18\\
~~~1~~~~0~~~~-7~~~-6~~~0\]
8 years ago
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satellite73:
i told you it was hard to write here
8 years ago
rootbeer003:
8 years ago
satellite73:
see if you can line them up
the 3 on further to the left
the 1 is directly under the top 1, but on the bottom row
8 years ago
rootbeer003:
8 years ago
satellite73:
second one is perfect
8 years ago
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rootbeer003:
8 years ago
satellite73:
now we have to write the answer, which you get from the bottom line the coefficents are \[1,0,-7,-6\] so your answer to the division problem is \[x^3-7x-6\] with no remainder
8 years ago
rootbeer003:
8 years ago
satellite73:
to finish part b), there is no remainder, so \(x-3\) goes in to \(f(x)\) evenly and so \(f(x)\) factors as \[x^4-3x^3-7x^2+15x+18=(x-3)(x^3-7x-6)\]
8 years ago
satellite73:
good enough, i would use a lower case x
8 years ago
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satellite73:
for part c) "factor completely" the answer is \[
8 years ago
satellite73:
\[(x - 3)^2 (x + 1) (x + 2)\]
8 years ago
satellite73:
how you are supposed to "show your work" for that one i have no idea
8 years ago
rootbeer003:
lets just skip the show ur work
8 years ago
satellite73:
ok fine last step is to graph
8 years ago
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satellite73:
make it look like the top one
8 years ago
rootbeer003:
ew
8 years ago
satellite73:
the curve should cross the x axis at -2 and -1 but just come down and touch it at 3 and go back up
8 years ago
rootbeer003:
8 years ago
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rootbeer003:
Golden.
8 years ago
satellite73:
good enug
8 years ago
rootbeer003:
yuuuuuuuuus
8 years ago
rootbeer003:
we have for more questions btw
8 years ago
rootbeer003:
four*
8 years ago
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satellite73:
lol not if they were as long as that one
8 years ago
rootbeer003:
8 years ago
satellite73:
a) \[4800\times (.98)^t\] where \(t\) is years after 2006
8 years ago
satellite73:
b) since 2018 is 12 years after 2006 it would be \[1800\times .98^{12}\] which you compute with a calculator
8 years ago
satellite73:
typo
8 years ago
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satellite73:
\[4800\times .98^{12}\]
8 years ago
rootbeer003:
u r so fast
8 years ago
rootbeer003:
3766.6402739270401602551808 do i put this
8 years ago
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rootbeer003:
8 years ago
satellite73:
no round, it is populaton
8 years ago
satellite73:
37667 would make more sense
8 years ago
rootbeer003:
3767
8 years ago
satellite73:
yeah that
8 years ago
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rootbeer003:
hows my grpah
8 years ago
satellite73:
usual crack added graph is beautiful
8 years ago
rootbeer003:
:')
8 years ago
rootbeer003:
8 years ago
satellite73:
i guess you are supposed to say there is a horizontal asymptote at \(y=0\) the x axis
8 years ago
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rootbeer003:
8 years ago
satellite73:
domain is tricky not sure how to answer it
maybe you are just supposed to day "all real numbers" although that is silly for a word problem but whatever
8 years ago
satellite73:
the range is from wherever you start to 0, not including 0
maybe you could say the range is from your starting value, \(4800\) to 0
8 years ago
rootbeer003:
8 years ago
satellite73:
ok good enuf
8 years ago
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satellite73:
i like the wolfram graph better, but whatever
8 years ago
rootbeer003:
8 years ago
rootbeer003:
i like sleeping better but here i am
8 years ago
satellite73:
next
8 years ago
satellite73:
i have no idea what a five number summery is
8 years ago
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satellite73:
nor do i know what a box and whisker plot is
you are on your own with that one
8 years ago
rootbeer003:
k
8 years ago
rootbeer003:
8 years ago
satellite73:
hold on we can do the first one by cheating
8 years ago
rootbeer003:
kk
8 years ago
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rootbeer003:
8 years ago
satellite73:
guess you cheated quicker than i did
where did you get that one?
8 years ago
satellite73:
ok you need to do some editing
8 years ago
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satellite73:
first of all, get rid of "best answer"
8 years ago
rootbeer003:
lol
8 years ago
satellite73:
then everything at the end, from 4 down, has nothing to do with this question
8 years ago
satellite73:
and finallly you still need a box and whisker plot
8 years ago
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satellite73:
here is a somewhat nicer one
8 years ago
rootbeer003:
it dont show nun
8 years ago
satellite73:
|dw:1497579802721:dw|
8 years ago
rootbeer003:
gorguss
8 years ago
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satellite73:
it does when you put the numbers in doe
8 years ago
rootbeer003:
ok go ahead doe
8 years ago
satellite73:
Enter comma separated data (numbers only):
8 years ago
satellite73:
i did but when i sent you the link it doesn't save it
8 years ago
rootbeer003:
send me the numbers
8 years ago
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satellite73:
the numbers in the question doe
8 years ago
rootbeer003:
but i might mess up doe
8 years ago
satellite73:
10,10,15,17,19,25 copy and paste lol
8 years ago
rootbeer003:
8 years ago
rootbeer003:
ok doe
8 years ago
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rootbeer003:
8 years ago
rootbeer003:
this is depressing
8 years ago
satellite73:
yeah usually it is put on its side for you high school students
8 years ago
satellite73:
like the one i wrote
8 years ago
satellite73:
ok good all you need is the standard deviation
and yes, this bull sht is depressing
most statistics is
8 years ago
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satellite73:
the standard deviation is computed in that yahoo answer, the one with the square root sign
8 years ago
rootbeer003:
8 years ago
rootbeer003:
i gotta put all that?
8 years ago
satellite73:
yes, that is the standard deviation apparently
8 years ago
rootbeer003:
all?
8 years ago
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satellite73:
hold on there is some mistake there
8 years ago
satellite73:
good thing i checked
8 years ago
rootbeer003:
das a good boi!
8 years ago
satellite73:
the data is \[10,10,15,17,19,25\]
8 years ago
rootbeer003:
but dis other guy has sum dif
8 years ago
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satellite73:
right
so the mean is \[\frac{10+10+15+17+19+25}{6}=16\]
8 years ago
rootbeer003:
8 years ago
rootbeer003:
btw do i keep the box lookin thing empty?
8 years ago
satellite73:
yeah box is right
8 years ago
satellite73:
five numbers summary is wrong though because the used the wrong numbers for yahoo
8 years ago
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rootbeer003:
great
8 years ago
satellite73:
i did it with an on line calculator, it is nothing
here
8 years ago
satellite73:
minimum is 10
first quartile 10
median 16
third quartile 19
maximum 25
8 years ago
satellite73:
i got that from here
8 years ago
rootbeer003:
do i erase a
8 years ago
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satellite73:
yeah copy what i wrote, not what yahoo wrote
8 years ago
rootbeer003:
do we gotta redo everything
8 years ago
satellite73:
the box plot is right
8 years ago
rootbeer003:
can we skip this and go back to it..
8 years ago
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satellite73:
the mean is right
8 years ago
satellite73:
what i wrote above is right just copy it
8 years ago
satellite73:
there is only one thing left do to, the standard deviation, which is not hard
8 years ago
rootbeer003:
8 years ago
satellite73:
yes standard deviation is all that is left
8 years ago
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satellite73:
i will write it out for you
8 years ago
rootbeer003:
8 years ago
satellite73:
\[(10-16)^2+(10-16)^2+(15-16)^2+(17-16)^2+(19-16)^2+(25-16)^2\]
\[=6^2+6^2+1+1+3^2+9^2\]
\[=164\]
\[\sqrt{164}=12.8\]
8 years ago
satellite73:
wrong but we can fix it in a jif
8 years ago
rootbeer003:
is it fixed
8 years ago
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satellite73:
\[\sqrt{\frac{164}{5}}=5.73\] now it is fixed
8 years ago
rootbeer003:
oh just the last part
8 years ago
satellite73:
skip the last line aboe
8 years ago
satellite73:
right
8 years ago
satellite73:
you need the \(168\)
then divide by 5, take the square root
8 years ago
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satellite73:
i mean 164,whatever
8 years ago
rootbeer003:
8 years ago
rootbeer003:
le juicy?
8 years ago
satellite73:
bingo
8 years ago
rootbeer003:
NEXt
8 years ago
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satellite73:
oui
8 years ago
satellite73:
oui,très juteux
8 years ago
satellite73:
next = new thread
8 years ago