Question

Anyone know how to make this true w/ parentheses? \[3^2−9\cdot2+1=8\]

Answer 1

@Hero I'm stumped, can you assist?

Answer 2

\(\color{red}{( \mod 16)}\)

which looks in appropriate, so there's error in Qu.....maybe 🤔

Answer 3

Perhaps the user made a typo:
\(\begin{align*}3^2−\left(9\cdot2\right)+1&=-8
\\9 - 18 + 1 &= -8
\\-9 + 1 &= -8
\\-8 &=-8\end{align*}\)

Answer 4

@Hero The question (copied from another site) is intended to ask how the equality can be made true:
3^2-9•2+1=8

Regardless, thanks for answering. This was from someone else who asked me to assist, but I was wondering if they made a typo somewhere as well.