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Solve 3^(2x) = 7^(x−1). −7.74293 7.74293 −1 1
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(First one)
take the natural log of each side ln[3^(2x)] = ln[7^(x−1)] bring the exponents down 2x*ln(3) = (x-1)*ln(7) distribute 2x*ln(3) = x*ln(7) - ln(7) move the variables to one side 2x*ln(3) - x*ln(7) = - ln(7) factor out x x(2*ln(3) - ln(7)) = - ln(7) then isolate x and plug in the logs into your calculator to solve
Okie, one second
I got
−7.74293
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good do you understand all the steps?
Yes maams :D, thank you!
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