Mathematics
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smithm29:
composite functions
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smithm29:
Vocaloid:
since it asks for f dot g, replace "x" with x^4 into f(x)
Vocaloid:
(x^4)^2 + 8(x^4) = ?
Vocaloid:
*** note: you are not given an x value so your answer should be a function not a number
smithm29:
is it x^8+8x^4?
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Vocaloid:
yes, that's your answer ~
smithm29:
Vocaloid:
similar, take f(x) = 7x - 9 and replace "x" with "x^2"
smithm29:
7x^2-9
Vocaloid:
good, that's your ans
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smithm29:
Vocaloid:
since h(x) = x^3 and f(x) = (4x^2 + 11)^3 then it's clear that g(x) is just the part inside the parentheses
Vocaloid:
|dw:1501519312764:dw|
smithm29:
im confused
Vocaloid:
so if f(x) = h dot g = (4x+11)^3
and h(x) = x^3
then g(x) is what gets replaced as x in h(x)
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Vocaloid:
|dw:1501519501200:dw|
Vocaloid:
|dw:1501519541905:dw|
Vocaloid:
*** so g(x) = 4x^2 + 11 *** i made a typo in the pic
smithm29:
Vocaloid:
if we plug in x = 6 into g(x) what do we get?
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smithm29:
3.5?
Vocaloid:
yeah, so since g(6) is a real number then it's in the domain of f dot g (answer choice 2)
smithm29:
Vocaloid:
if we plug x = 3 into g(x) what do we get?
smithm29:
-16
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Vocaloid:
check your math again
-4(3) + 4 = ?
smithm29:
-8
Vocaloid:
good, now if x = -8 what does f(x) = ?
smithm29:
it says error bc u cant 2root a neg.
Vocaloid:
good, so 3 can't be in the domain of f dot g
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Vocaloid:
ans choice 2
smithm29:
Vocaloid:
x = 5, g(x) = ?
smithm29:
-49?
Vocaloid:
good, and if x = -49, f(x) = ?
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smithm29:
it cant
Vocaloid:
good, so 5 isn't in the domain of f dot g
smithm29:
Vocaloid:
same thing as before: x = -7, g(x) = ?
smithm29:
-68?
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Vocaloid:
good, so if x = -68 then f(x) = ?
smithm29:
cant
Vocaloid:
good so -7 is not in the domain
smithm29:
Vocaloid:
g(x) has to be positive so x - 4 has to be positive
so x must be greater than 4
which choice matches?
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smithm29:
5
Vocaloid:
good, that's your answer
smithm29:
Vocaloid:
g(x) has to be positive so x + 6 has to be positive, therefore x > -6
Vocaloid:
so which choice matches?
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smithm29:
6
Vocaloid:
good, that's your answer
smithm29:
Vocaloid:
the minumum value of a square root function occurs when the inside of the radical is a 0
so x + 6 = 0
x = ?
smithm29:
-6
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Vocaloid:
good so -6 = your ans
smithm29:
Vocaloid:
same thing as before, x - 6 = 0 so x = ?
smithm29:
6
Vocaloid:
good, so 6 = your ans
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smithm29:
Vocaloid:
ok, since f(x) = 1/x, then x cannot be equal to 0
Vocaloid:
therefore: x^2 - 4x = 0
if you solve this you will get your answers
know how to do it?
smithm29:
no
Vocaloid:
start by factoring out x
x^2 - 4x
becomes
x(x-4) = 0
therefore:
x = 0 and x - 4 = 0 so x = ?
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smithm29:
4
Vocaloid:
good, so 0 and 4 are your answers (include both)
smithm29:
Vocaloid:
same thing
x^2 - 6x = 0
x(x-6) = 0
x = 0 and x - 6 = 0 so x = ?
smithm29:
6
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Vocaloid:
good, so 0,6 are your answers
smithm29:
Vocaloid:
subtract 4 from the x-coordinate
smithm29:
Vocaloid:
I'm a little uncertain but I would multiply the x-coordinate by 2
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smithm29:
THAT WAS RIGHT
Vocaloid:
yeah I just realized you posted a similar question before and I accidentally gave you the wrong method :S
smithm29:
lol its cool i wouldve done it all wrong
Vocaloid:
if you have a fraction inside the parentheses you would multiply the x coordinate by the denominator
smithm29:
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Vocaloid:
so I believe we would take the reciprocal and multiply the x-coordinate by (-4/3)
smithm29:
(-36,2)?
Vocaloid:
horizontal transformations were never my strong suit
Vocaloid:
hm
Vocaloid:
9*(-4/3) = ?
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smithm29:
oh I thought u would have to multiply 9 by -4
Vocaloid:
yeah I should have mentioned that rule only applies when the numerator is 1
smithm29:
oh
Vocaloid:
otherwise I believe you're supposed to flip the fraction then multiply
Vocaloid:
9*(-4/3) = -12 so I ~think~ the answer is (-12,2)?
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smithm29:
yup
smithm29:
Vocaloid:
divide the x-coordinate by 3
smithm29:
smithm29:
so (-8,-4)?
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Vocaloid:
multiply the y-coordinate by (1/2)
Vocaloid:
the (1/2) is outside the parentheses so it's different
smithm29:
oh
Vocaloid:
if it's inside we change the x-coordinate, if it's outside we change y
smithm29:
(-4,-2)?
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smithm29:
is this right bc i wasnt to sure on my calculating?
Vocaloid:
yeah that's the answer, good
smithm29:
Vocaloid:
same thing, multiply y by (1/2)
smithm29:
the y?
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Vocaloid:
the y-coordinate, yeah
smithm29:
1,-4?
Vocaloid:
yup, that's the answer
smithm29:
i have on more lesson and its only 5 questions
Vocaloid:
sure go for it
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smithm29:
Vocaloid:
we did something like this yesterday
airplane + wind = 1680/4
airplane - wind = 1680/5
solve for airplane by adding the equations together
smithm29:
1680+5=420
1680-5=336
smithm29:
?
Vocaloid:
hmm not quite
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Vocaloid:
airplane + airplane = 2*airplane (or 2x if you want to use their variables)
Vocaloid:
1680/4 + 1680/5 = 756
Vocaloid:
wind - wind = 0
Vocaloid:
so 2*airplane = 756
airplane = ?
smithm29:
so the speed of the plane when theres no wind is 756?
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Vocaloid:
nope not quite
Vocaloid:
2* airplane speed = 756
airplane speed = ?
smithm29:
378
smithm29:
is the answer?
Vocaloid:
yes, good
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smithm29:
Vocaloid:
it's 25, we've done this one before :S
smithm29:
i think weve done most of these but i dont remeber the answers
smithm29:
Vocaloid:
load should be <= 150
mail should be <= 150000
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Vocaloid:
"as many as" usually means <=
smithm29:
so the 2nd one?
Vocaloid:
yeah
smithm29:
Vocaloid:
burgers and bratwurst >= 90
budget <= 120
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smithm29:
smithm29:
last one
Vocaloid:
more expensive tree >= less expensive tree
budget <= 95,000
smithm29:
which one would that be?
Vocaloid:
the more expensive tree is y
the less expensive tree is x
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Vocaloid:
y >= x
budget <= 95,000
Vocaloid:
you can flip y>= x to get x<=y...