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Mathematics 6 Online
smithm29:

composite functions

smithm29:

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Vocaloid:

since it asks for f dot g, replace "x" with x^4 into f(x)

Vocaloid:

(x^4)^2 + 8(x^4) = ?

Vocaloid:

*** note: you are not given an x value so your answer should be a function not a number

smithm29:

is it x^8+8x^4?

Vocaloid:

yes, that's your answer ~

smithm29:

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Vocaloid:

similar, take f(x) = 7x - 9 and replace "x" with "x^2"

smithm29:

7x^2-9

Vocaloid:

good, that's your ans

smithm29:

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Vocaloid:

since h(x) = x^3 and f(x) = (4x^2 + 11)^3 then it's clear that g(x) is just the part inside the parentheses

Vocaloid:

|dw:1501519312764:dw|

smithm29:

im confused

Vocaloid:

so if f(x) = h dot g = (4x+11)^3 and h(x) = x^3 then g(x) is what gets replaced as x in h(x)

Vocaloid:

|dw:1501519501200:dw|

Vocaloid:

|dw:1501519541905:dw|

Vocaloid:

*** so g(x) = 4x^2 + 11 *** i made a typo in the pic

smithm29:

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Vocaloid:

if we plug in x = 6 into g(x) what do we get?

smithm29:

3.5?

Vocaloid:

yeah, so since g(6) is a real number then it's in the domain of f dot g (answer choice 2)

smithm29:

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Vocaloid:

if we plug x = 3 into g(x) what do we get?

smithm29:

-16

Vocaloid:

check your math again -4(3) + 4 = ?

smithm29:

-8

Vocaloid:

good, now if x = -8 what does f(x) = ?

smithm29:

it says error bc u cant 2root a neg.

Vocaloid:

good, so 3 can't be in the domain of f dot g

Vocaloid:

ans choice 2

smithm29:

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Vocaloid:

x = 5, g(x) = ?

smithm29:

-49?

Vocaloid:

good, and if x = -49, f(x) = ?

smithm29:

it cant

Vocaloid:

good, so 5 isn't in the domain of f dot g

smithm29:

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Vocaloid:

same thing as before: x = -7, g(x) = ?

smithm29:

-68?

Vocaloid:

good, so if x = -68 then f(x) = ?

smithm29:

cant

Vocaloid:

good so -7 is not in the domain

smithm29:

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Vocaloid:

g(x) has to be positive so x - 4 has to be positive so x must be greater than 4 which choice matches?

smithm29:

5

Vocaloid:

good, that's your answer

smithm29:

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Vocaloid:

g(x) has to be positive so x + 6 has to be positive, therefore x > -6

Vocaloid:

so which choice matches?

smithm29:

6

Vocaloid:

good, that's your answer

smithm29:

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Vocaloid:

the minumum value of a square root function occurs when the inside of the radical is a 0 so x + 6 = 0 x = ?

smithm29:

-6

Vocaloid:

good so -6 = your ans

smithm29:

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Vocaloid:

same thing as before, x - 6 = 0 so x = ?

smithm29:

6

Vocaloid:

good, so 6 = your ans

smithm29:

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Vocaloid:

ok, since f(x) = 1/x, then x cannot be equal to 0

Vocaloid:

therefore: x^2 - 4x = 0 if you solve this you will get your answers know how to do it?

smithm29:

no

Vocaloid:

start by factoring out x x^2 - 4x becomes x(x-4) = 0 therefore: x = 0 and x - 4 = 0 so x = ?

smithm29:

4

Vocaloid:

good, so 0 and 4 are your answers (include both)

smithm29:

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Vocaloid:

same thing x^2 - 6x = 0 x(x-6) = 0 x = 0 and x - 6 = 0 so x = ?

smithm29:

6

Vocaloid:

good, so 0,6 are your answers

smithm29:

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Vocaloid:

subtract 4 from the x-coordinate

smithm29:

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Vocaloid:

I'm a little uncertain but I would multiply the x-coordinate by 2

smithm29:

THAT WAS RIGHT

Vocaloid:

yeah I just realized you posted a similar question before and I accidentally gave you the wrong method :S

smithm29:

lol its cool i wouldve done it all wrong

Vocaloid:

if you have a fraction inside the parentheses you would multiply the x coordinate by the denominator

smithm29:

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Vocaloid:

so I believe we would take the reciprocal and multiply the x-coordinate by (-4/3)

smithm29:

(-36,2)?

Vocaloid:

horizontal transformations were never my strong suit

Vocaloid:

hm

Vocaloid:

9*(-4/3) = ?

smithm29:

oh I thought u would have to multiply 9 by -4

Vocaloid:

yeah I should have mentioned that rule only applies when the numerator is 1

smithm29:

oh

Vocaloid:

otherwise I believe you're supposed to flip the fraction then multiply

Vocaloid:

9*(-4/3) = -12 so I ~think~ the answer is (-12,2)?

smithm29:

yup

smithm29:

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Vocaloid:

divide the x-coordinate by 3

smithm29:

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smithm29:

so (-8,-4)?

Vocaloid:

multiply the y-coordinate by (1/2)

Vocaloid:

the (1/2) is outside the parentheses so it's different

smithm29:

oh

Vocaloid:

if it's inside we change the x-coordinate, if it's outside we change y

smithm29:

(-4,-2)?

smithm29:

is this right bc i wasnt to sure on my calculating?

Vocaloid:

yeah that's the answer, good

smithm29:

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Vocaloid:

same thing, multiply y by (1/2)

smithm29:

the y?

Vocaloid:

the y-coordinate, yeah

smithm29:

1,-4?

Vocaloid:

yup, that's the answer

smithm29:

i have on more lesson and its only 5 questions

Vocaloid:

sure go for it

smithm29:

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Vocaloid:

we did something like this yesterday airplane + wind = 1680/4 airplane - wind = 1680/5 solve for airplane by adding the equations together

smithm29:

1680+5=420 1680-5=336

smithm29:

?

Vocaloid:

hmm not quite

Vocaloid:

airplane + airplane = 2*airplane (or 2x if you want to use their variables)

Vocaloid:

1680/4 + 1680/5 = 756

Vocaloid:

wind - wind = 0

Vocaloid:

so 2*airplane = 756 airplane = ?

smithm29:

so the speed of the plane when theres no wind is 756?

Vocaloid:

nope not quite

Vocaloid:

2* airplane speed = 756 airplane speed = ?

smithm29:

378

smithm29:

is the answer?

Vocaloid:

yes, good

smithm29:

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Vocaloid:

it's 25, we've done this one before :S

smithm29:

i think weve done most of these but i dont remeber the answers

smithm29:

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Vocaloid:

load should be <= 150 mail should be <= 150000

Vocaloid:

"as many as" usually means <=

smithm29:

so the 2nd one?

Vocaloid:

yeah

smithm29:

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Vocaloid:

burgers and bratwurst >= 90 budget <= 120

smithm29:

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smithm29:

last one

Vocaloid:

more expensive tree >= less expensive tree budget <= 95,000

smithm29:

which one would that be?

Vocaloid:

the more expensive tree is y the less expensive tree is x

Vocaloid:

y >= x budget <= 95,000

Vocaloid:

you can flip y>= x to get x<=y...

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