Question

https://s1.postimg.org/8hglzf8ldb/Capture.png

Answer 1

let's start with x-intercepts please

where does the graph touch the x-axis?

Answer 2

0 and 4

Answer 3

awesome

what about y-intercepts?

Answer 4

0,0 0,4

Answer 5

for x

Answer 6

good, what about y?

Answer 7

0,0

Answer 8

good, so what's the answer?

Answer 9

c yay i'm learning something

Answer 10

good, c

Answer 11

https://s1.postimg.org/9sltc9b62n/Capture.png

Answer 12

at x = 3, what does the graph equal?

Answer 13

6

Answer 14

good, so a is the correct answer

Answer 15

https://s1.postimg.org/1u6z9iz7of/Capture.png

Answer 16

hint: what x-value has a "gap" or "jump" in the graph?

Answer 17

removable at -4 cause of the hole

Answer 18

close but not quite

it's not removable because there's no way to "plug" the hole by re-writing the function

Answer 19

it's a jump discontinuity

Answer 20

it's jump i see the jump now

Answer 21

^removable looks more like that

Answer 22

https://s1.postimg.org/1y3clf8vbj/Capture.png

Answer 23

hint: is it symmetric about the y-axis?

Answer 24

is this one neither it's not symmetrical at all

Answer 25

good, neither

Answer 26

https://s1.postimg.org/2nm4xrwrmn/Capture.png

Answer 27

a?

Answer 28

the left side has an asymptote (graph isn't drawn well) but the right side doesn't

Answer 29

as x ---> infinity is the graph approaching + infinity or -infinity?

Answer 30

it's c then

Answer 31

nope

Answer 32

please answer my question

Answer 33

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
as x ---> infinity is the graph approaching + infinity or -infinity?
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 34

aren;t both approaching infinity

Answer 35

again, please consider my question

Answer 36

positive?

Answer 37

I'm confused

Answer 38

ok, the draw tool isn't working for me so let me try something else

Answer 39

notice how the graph on the right hand side is pointing to negative values as x goes to infinity?

Answer 40

yes so that is x

Answer 41

so does the graph go towards +infinity or -infinity as x ---> infinity?

Answer 42

- infinity

Answer 43

good

Answer 44

now let's consider the left side

there is an asymptote at y = -1

so as x ----> -infinity, the graph approaches -1

Answer 45

so which answer choice matches?

Answer 46

so it's d

Answer 47

yes good

Answer 48

https://s1.postimg.org/4s7rwoag3j/Capture.png

Answer 49

promise almost done

Answer 50

easiest way would just be to graph it

Answer 51

http://www.wolframalpha.com/

plug in y = x^(1/5)

Answer 52

just look at the real part (not the imaginary part)

Answer 53

the function is odd

Answer 54

hm

Answer 55

what about the domain/range?

Answer 56

mathway said it's odd

Answer 57

f(x)5 square x is odd look at graph

Answer 58

continuous

Answer 59

- infinity positive infintity for both

Answer 60

@Vocaloid

Answer 61

i'm confused mathway must be wrong

Answer 62

this software isn't very good

Answer 63

it gives me different answers for x^0.2 and x^(1/5) even though they should be the same

Answer 64

did you plug in f(x)=5 square root x

Answer 65

it's not 5 square root x

Answer 66

it's x to the fifth root

Answer 67

anyway I think you're right for the domain and range

Answer 68

oh there's a difference

Answer 69

so the domain and range are both -infinity to +infinity
it's odd

what about intervals of increase/decrease?

Answer 70

so is it neither

Answer 71

neither what?

Answer 72

it should be odd, I made a mistake earlier

Answer 73

gtg

Answer 74

wait now you have really confused me

Answer 75

0, infinity increasing
-infinity, 0 decreasing

Answer 76

ni/o asymptotes

Answer 77

discontinuous

Answer 78

@Vocaloid end behavior?