Question

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What percent of those who passed the second exam also passed the first exam?
80% <<<<<
12%
30%
48%

Answer 1

@dude

Answer 2

How did you get 80? Just curious

Answer 3

Tbh I searched up :/

Answer 4

easiest way would just be to assume a class of 100

Answer 5

60 people passed exam 2
48 people passed exam 1 and 2

so it would be (people who passed both exams)/(people who passed exam 2)

Answer 6

So I was right? :O

Answer 7

yes, but do you understand why though? that's the important part

Answer 8

No maams D;

Answer 9

"What percent of those who passed the second exam also passed the first exam?"

Answer 10

"of those" implies that "people who passed the second exam" is the denominator

Answer 11

now, we want to know, out of those 60 people, what percent passed exam 1 AND exam 2

Answer 12

so 48 out of those 60 people passed exam 1 AND exam 2

Answer 13

so our answer is (48/60)*100 (to convert to a percent)

Answer 14

the general rule for percents is: "the percent of (A) out of (B) is 100*(A/B)"

Answer 15

I understand now :O thank you for the explanation! Sorry I was lagging really bad on Firefox XD

Answer 16

Venn diagrams are there for a reason