Ask your own question, for FREE!
Mathematics 16 Online
silvernight269:

the equation to convert Celsius temperature C to kelvin temperature is shown. K=C+273 (0,273) (-273,0) determine the C-andK-intercept and describe what the intercepts mean in this situation.

Vocaloid:

K is our independent variable and C is our dependent variable so we would treat K the way we normally treat y on an x-y plane, and treat C as x

silvernight269:

i still don't get it

Vocaloid:

usually equations are written as independent = dependent with some sort of addition/subtraction/multiplication/division done to it

Vocaloid:

are you familiar with x-intercepts and y-intercepts?

silvernight269:

i get this part

Vocaloid:

it's the same concept, just using K and C instead of x and y

silvernight269:

oh. i see

silvernight269:

yes

Vocaloid:

(0,273) means C = 0 and K = 273, so this is our "K-intercept"

Vocaloid:

(-273,0) means C = -273 and K = 0 so this is our "C-intercept"

Vocaloid:

it might make more sense if we graph this function as an x-y plane

silvernight269:

and then (-273,0) means C=-273 and K=0 is our c intercept?

Vocaloid:

yes

silvernight269:

ok

Vocaloid:

1 attachment
Vocaloid:

when C = 0 the graph crosses the K-intercept when K = 0 the graph crosses the C-intercept works the same way for x and y

Vocaloid:

anyway, as for what they mean:

Vocaloid:

The K-intercept is the value of temperature in degrees Kelvin when C = 0 degrees The C-intercept is the value of the temperature in degrees Celcius when K = 0 degrees

silvernight269:

i see

Vocaloid:

anyway, that's pretty much the extent of the question, look over it a bit and let me know if you have any questions ^^

silvernight269:

ok. thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!