What is the equation, in point-slope form, for a line that goes through (8,−4) and has a slope of −56 ?

y+4=−56(x−8)

y+4=−56(x+8)

y−4=−56(x+8)

y−4=−56(x−8)

Question

What is the equation, in point-slope form, for a line that goes through (8,−4) and has a slope of −56 ?

y+4=−56(x−8)

y+4=−56(x+8)

y−4=−56(x+8)

y−4=−56(x−8)

563blackghost · Answer

point-slope is setup as $\large\bf{y-y_{1}=m(x-x_{1})}$.

$\bf{m}$ is the slope. $\bf{(x_{1},y_{1})}$ is the point given. So we plug.

$\large\bf{y+4=-56(x-8)}$

morganislame · Answer

Thank you so much. That is what i was thinking but was a little bit confused.

563blackghost · Answer

np :)