Question

What is the equation, in point-slope form, for a line that goes through (8,−4) and has a slope of −56 ?

y+4=−56(x−8)

y+4=−56(x+8)

y−4=−56(x+8)

y−4=−56(x−8)

Answer 1

point-slope is setup as \(\large\bf{y-y_{1}=m(x-x_{1})}\).

\(\bf{m}\) is the slope. \(\bf{(x_{1},y_{1})}\) is the point given. So we plug.

\(\large\bf{y+4=-56(x-8)}\)

Answer 2

Thank you so much. That is what i was thinking but was a little bit confused.

Answer 3

np :)