Question

Please Help Me!!
Evaluate fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.

9 to the power of negative 1 over 2
9 to the power of negative 1 over 4
9
9^2

Answer 1

@Vocaloid

Answer 2

\[\frac{ \sqrt[4]{9}*\sqrt{9} }{ (\sqrt[4]{9})^{5} }\]

Answer 3

this? :S

Answer 4

Yes! How did you do that? @Vocaloid

Answer 5

Using LaTeX, you can see a tutorial I made here:
WARNING IT DOES TAKE A WHILE TO LOAD
questioncove.com/updates/5654ccade4b0af360a7ccd28

Answer 6

well we can do a bit of re-writing to get:

Answer 7

\[\frac{ \sqrt[4]{9}*3 }{ \sqrt[4]{9}*\sqrt[4]{9}*\sqrt[4]{9}*\sqrt[4]{9}*\sqrt[4]{9} }\]

Answer 8

the 4th root of 9 times itself 4 times is just 9

Answer 9

\[\frac{ \sqrt[4]{9} * 3}{ 9 * \sqrt[4]{9} }\]

Answer 10

then we just cross out the last 4th root of 9

and then we just get 3/9 = 1/3

Answer 11

But that is not an answer :(

Answer 12

oh, well we can re-write 1/3 as 1/sqrt(9) which is just 9^(-1/2)

Answer 13

so the first option

Answer 14

Oh that makes sense thank you @Vocaloid